返回特征解读

1996 年全国高中数学联赛(学生版)

books/national_high_school_league_students/papers/competition-national-league-1996.pdf · HS-MATH-1024-v2.1-solution-aware

160 个小问/题组
1

一试 · 第一试(10月13日上午8:00-9:20) 一、选择题(本题满分 36 分,每题 6 分) · 平面几何

把圆 x2+(y1)2=1\htmlData{tutor-start=0,tutor-end=1}{x}^{\htmlData{tutor-start=3,tutor-end=4}{2}}\htmlData{tutor-start=5,tutor-end=6}{+}\htmlData{tutor-start=6,tutor-end=7}{(}\htmlData{tutor-start=7,tutor-end=8}{y}\htmlData{tutor-start=8,tutor-end=9}{-}\htmlData{tutor-start=9,tutor-end=10}{1}\htmlData{tutor-start=10,tutor-end=11}{)}^{\htmlData{tutor-start=13,tutor-end=14}{2}}\htmlData{tutor-start=15,tutor-end=16}{=}\htmlData{tutor-start=16,tutor-end=17}{1} 与椭圆 9x2+(y+1)2=9\htmlData{tutor-start=0,tutor-end=1}{9}\htmlData{tutor-start=1,tutor-end=2}{x}^{\htmlData{tutor-start=4,tutor-end=5}{2}}\htmlData{tutor-start=6,tutor-end=7}{+}\htmlData{tutor-start=7,tutor-end=8}{(}\htmlData{tutor-start=8,tutor-end=9}{y}\htmlData{tutor-start=9,tutor-end=10}{+}\htmlData{tutor-start=10,tutor-end=11}{1}\htmlData{tutor-start=11,tutor-end=12}{)}^{\htmlData{tutor-start=14,tutor-end=15}{2}}\htmlData{tutor-start=16,tutor-end=17}{=}\htmlData{tutor-start=17,tutor-end=18}{9} 的公共点,用线段连接起来所得到的图形为( ) (A) 线段 (B) 不等边三角形 (C) 等边三角形 (D) 四边形

题解状态:标准答案与规范题解待补充

题目标签:FIRST-CHOICE-P1

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2

一试 · 第一试(10月13日上午8:00-9:20) 一、选择题(本题满分 36 分,每题 6 分) · 代数

等比数列 {an}\htmlData{tutor-start=0,tutor-end=2}{\{}\htmlData{tutor-start=2,tutor-end=3}{a}_{\htmlData{tutor-start=5,tutor-end=6}{n}}\htmlData{tutor-start=7,tutor-end=9}{\}} 的首项 a1=1536\htmlData{tutor-start=0,tutor-end=1}{a}_{\htmlData{tutor-start=3,tutor-end=4}{1}}\htmlData{tutor-start=5,tutor-end=6}{=}\htmlData{tutor-start=6,tutor-end=7}{1}\htmlData{tutor-start=7,tutor-end=8}{5}\htmlData{tutor-start=8,tutor-end=9}{3}\htmlData{tutor-start=9,tutor-end=10}{6},公比 q=12\htmlData{tutor-start=0,tutor-end=1}{q}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=3}{-}\frac{\htmlData{tutor-start=9,tutor-end=10}{1}}{\htmlData{tutor-start=12,tutor-end=13}{2}},用 πn\htmlData{tutor-start=0,tutor-end=3}{\pi}_{\htmlData{tutor-start=5,tutor-end=6}{n}} 表示它的前 n\htmlData{tutor-start=0,tutor-end=1}{n} 项之积。则 πn(nN)\pi_{n} (n \in \mathbb{N}^*) 最大的是( ) (A) π9\htmlData{tutor-start=0,tutor-end=3}{\pi}_{\htmlData{tutor-start=5,tutor-end=6}{9}} (B) π11\htmlData{tutor-start=0,tutor-end=3}{\pi}_{\htmlData{tutor-start=5,tutor-end=6}{1}\htmlData{tutor-start=6,tutor-end=7}{1}} (C) π12\htmlData{tutor-start=0,tutor-end=3}{\pi}_{\htmlData{tutor-start=5,tutor-end=6}{1}\htmlData{tutor-start=6,tutor-end=7}{2}} (D) π13\htmlData{tutor-start=0,tutor-end=3}{\pi}_{\htmlData{tutor-start=5,tutor-end=6}{1}\htmlData{tutor-start=6,tutor-end=7}{3}}

题解状态:标准答案与规范题解待补充

题目标签:FIRST-CHOICE-P2

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3

一试 · 第一试(10月13日上午8:00-9:20) 一、选择题(本题满分 36 分,每题 6 分) · 数论

存在整数 n\htmlData{tutor-start=0,tutor-end=1}{n},使 p+pn+n\sqrt{\htmlData{tutor-start=6,tutor-end=7}{p}\htmlData{tutor-start=7,tutor-end=8}{+}\htmlData{tutor-start=8,tutor-end=9}{p}\htmlData{tutor-start=9,tutor-end=10}{n}}\htmlData{tutor-start=11,tutor-end=12}{+}\sqrt{\htmlData{tutor-start=18,tutor-end=19}{n}} 是整数的质数 p\htmlData{tutor-start=0,tutor-end=1}{p}( ) (A) 不存在 (B) 只有一个 (C) 多于一个,但为有限个 (D) 有无穷多个

题解状态:标准答案与规范题解待补充

题目标签:FIRST-CHOICE-P3

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4

一试 · 第一试(10月13日上午8:00-9:20) 一、选择题(本题满分 36 分,每题 6 分) · 数学竞赛/待细分

x(12,0)\htmlData{tutor-start=0,tutor-end=1}{x} \htmlData{tutor-start=2,tutor-end=6}{\in }\htmlData{tutor-start=6,tutor-end=7}{(}\htmlData{tutor-start=7,tutor-end=8}{-}\frac{\htmlData{tutor-start=14,tutor-end=15}{1}}{\htmlData{tutor-start=17,tutor-end=18}{2}}\htmlData{tutor-start=19,tutor-end=20}{,} \htmlData{tutor-start=21,tutor-end=22}{0}\htmlData{tutor-start=22,tutor-end=23}{)},以下三个数 σ1=cos(sinxπ)\htmlData{tutor-start=0,tutor-end=6}{\sigma}_{\htmlData{tutor-start=8,tutor-end=9}{1}}\htmlData{tutor-start=10,tutor-end=11}{=}\cos\htmlData{tutor-start=15,tutor-end=16}{(}\sin \htmlData{tutor-start=21,tutor-end=22}{x} \htmlData{tutor-start=23,tutor-end=26}{\pi}\htmlData{tutor-start=26,tutor-end=27}{)}σ2=sin(cosxπ)\htmlData{tutor-start=0,tutor-end=6}{\sigma}_{\htmlData{tutor-start=8,tutor-end=9}{2}}\htmlData{tutor-start=10,tutor-end=11}{=}\sin\htmlData{tutor-start=15,tutor-end=16}{(}\cos \htmlData{tutor-start=21,tutor-end=22}{x} \htmlData{tutor-start=23,tutor-end=26}{\pi}\htmlData{tutor-start=26,tutor-end=27}{)}σ3=cos(x+1)π\htmlData{tutor-start=0,tutor-end=6}{\sigma}_{\htmlData{tutor-start=8,tutor-end=9}{3}}\htmlData{tutor-start=10,tutor-end=11}{=}\cos\htmlData{tutor-start=15,tutor-end=16}{(}\htmlData{tutor-start=16,tutor-end=17}{x}\htmlData{tutor-start=17,tutor-end=18}{+}\htmlData{tutor-start=18,tutor-end=19}{1}\htmlData{tutor-start=19,tutor-end=20}{)}\htmlData{tutor-start=20,tutor-end=23}{\pi} 的大小关系是( ) (A) σ3<σ2<σ1\htmlData{tutor-start=0,tutor-end=6}{\sigma}_{\htmlData{tutor-start=8,tutor-end=9}{3}} \htmlData{tutor-start=11,tutor-end=12}{<} \htmlData{tutor-start=13,tutor-end=19}{\sigma}_{\htmlData{tutor-start=21,tutor-end=22}{2}} \htmlData{tutor-start=24,tutor-end=25}{<} \htmlData{tutor-start=26,tutor-end=32}{\sigma}_{\htmlData{tutor-start=34,tutor-end=35}{1}} (B) σ1<σ3<σ2\htmlData{tutor-start=0,tutor-end=6}{\sigma}_{\htmlData{tutor-start=8,tutor-end=9}{1}} \htmlData{tutor-start=11,tutor-end=12}{<} \htmlData{tutor-start=13,tutor-end=19}{\sigma}_{\htmlData{tutor-start=21,tutor-end=22}{3}} \htmlData{tutor-start=24,tutor-end=25}{<} \htmlData{tutor-start=26,tutor-end=32}{\sigma}_{\htmlData{tutor-start=34,tutor-end=35}{2}} (C) σ3<σ1<σ2\htmlData{tutor-start=0,tutor-end=6}{\sigma}_{\htmlData{tutor-start=8,tutor-end=9}{3}} \htmlData{tutor-start=11,tutor-end=12}{<} \htmlData{tutor-start=13,tutor-end=19}{\sigma}_{\htmlData{tutor-start=21,tutor-end=22}{1}} \htmlData{tutor-start=24,tutor-end=25}{<} \htmlData{tutor-start=26,tutor-end=32}{\sigma}_{\htmlData{tutor-start=34,tutor-end=35}{2}} (D) σ2<σ3<σ1\htmlData{tutor-start=0,tutor-end=6}{\sigma}_{\htmlData{tutor-start=8,tutor-end=9}{2}} \htmlData{tutor-start=11,tutor-end=12}{<} \htmlData{tutor-start=13,tutor-end=19}{\sigma}_{\htmlData{tutor-start=21,tutor-end=22}{3}} \htmlData{tutor-start=24,tutor-end=25}{<} \htmlData{tutor-start=26,tutor-end=32}{\sigma}_{\htmlData{tutor-start=34,tutor-end=35}{1}}

题解状态:标准答案与规范题解待补充

题目标签:FIRST-CHOICE-P4

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

5

一试 · 第一试(10月13日上午8:00-9:20) 一、选择题(本题满分 36 分,每题 6 分) · 代数

如果在区间 [1,2]\htmlData{tutor-start=0,tutor-end=1}{[}\htmlData{tutor-start=1,tutor-end=2}{1}\htmlData{tutor-start=2,tutor-end=3}{,} \htmlData{tutor-start=4,tutor-end=5}{2}\htmlData{tutor-start=5,tutor-end=6}{]} 上函数 f(x)=x2+px+q\htmlData{tutor-start=0,tutor-end=1}{f}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{x}\htmlData{tutor-start=3,tutor-end=4}{)}\htmlData{tutor-start=4,tutor-end=5}{=}\htmlData{tutor-start=5,tutor-end=6}{x}^{\htmlData{tutor-start=8,tutor-end=9}{2}}\htmlData{tutor-start=10,tutor-end=11}{+}\htmlData{tutor-start=11,tutor-end=12}{p}\htmlData{tutor-start=12,tutor-end=13}{x}\htmlData{tutor-start=13,tutor-end=14}{+}\htmlData{tutor-start=14,tutor-end=15}{q}g(x)=x+1x2\htmlData{tutor-start=0,tutor-end=1}{g}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{x}\htmlData{tutor-start=3,tutor-end=4}{)}\htmlData{tutor-start=4,tutor-end=5}{=}\htmlData{tutor-start=5,tutor-end=6}{x}\htmlData{tutor-start=6,tutor-end=7}{+}\frac{\htmlData{tutor-start=13,tutor-end=14}{1}}{\htmlData{tutor-start=16,tutor-end=17}{x}^{\htmlData{tutor-start=19,tutor-end=20}{2}}} 在同一点取相同的最小值,那么 f(x)\htmlData{tutor-start=0,tutor-end=1}{f}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{x}\htmlData{tutor-start=3,tutor-end=4}{)} 在该区间上的最大值是( ) (A) 4+113223+43\htmlData{tutor-start=0,tutor-end=1}{4}\htmlData{tutor-start=1,tutor-end=2}{+}\frac{\htmlData{tutor-start=8,tutor-end=9}{1}\htmlData{tutor-start=9,tutor-end=10}{1}\htmlData{tutor-start=10,tutor-end=11}{3}}{\htmlData{tutor-start=13,tutor-end=14}{2}}\sqrt[\htmlData{tutor-start=21,tutor-end=22}{3}]{\htmlData{tutor-start=24,tutor-end=25}{2}}\htmlData{tutor-start=26,tutor-end=27}{+}\sqrt[\htmlData{tutor-start=33,tutor-end=34}{3}]{\htmlData{tutor-start=36,tutor-end=37}{4}} (B) 453223+43\htmlData{tutor-start=0,tutor-end=1}{4}\htmlData{tutor-start=1,tutor-end=2}{-}\frac{\htmlData{tutor-start=8,tutor-end=9}{5}\htmlData{tutor-start=9,tutor-end=10}{3}}{\htmlData{tutor-start=12,tutor-end=13}{2}}\sqrt[\htmlData{tutor-start=20,tutor-end=21}{3}]{\htmlData{tutor-start=23,tutor-end=24}{2}}\htmlData{tutor-start=25,tutor-end=26}{+}\sqrt[\htmlData{tutor-start=32,tutor-end=33}{3}]{\htmlData{tutor-start=35,tutor-end=36}{4}} (C) 113223+43\htmlData{tutor-start=0,tutor-end=1}{1}\htmlData{tutor-start=1,tutor-end=2}{-}\frac{\htmlData{tutor-start=8,tutor-end=9}{1}\htmlData{tutor-start=9,tutor-end=10}{3}}{\htmlData{tutor-start=12,tutor-end=13}{2}}\sqrt[\htmlData{tutor-start=20,tutor-end=21}{3}]{\htmlData{tutor-start=23,tutor-end=24}{2}}\htmlData{tutor-start=25,tutor-end=26}{+}\sqrt[\htmlData{tutor-start=32,tutor-end=33}{3}]{\htmlData{tutor-start=35,tutor-end=36}{4}} (D) 以上答案都不对

题解状态:标准答案与规范题解待补充

题目标签:FIRST-CHOICE-P5

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6

一试 · 第一试(10月13日上午8:00-9:20) 一、选择题(本题满分 36 分,每题 6 分) · 平面几何

高为 8 的圆台内有一个半径为 2 的球 O1\htmlData{tutor-start=0,tutor-end=1}{O}_{\htmlData{tutor-start=3,tutor-end=4}{1}},球心 O1\htmlData{tutor-start=0,tutor-end=1}{O}_{\htmlData{tutor-start=3,tutor-end=4}{1}} 在圆台的轴上,球 O1\htmlData{tutor-start=0,tutor-end=1}{O}_{\htmlData{tutor-start=3,tutor-end=4}{1}} 与圆台的上底面、侧面都相切,圆台内可再放入一个半径为 3 的球 O2\htmlData{tutor-start=0,tutor-end=1}{O}_{\htmlData{tutor-start=3,tutor-end=4}{2}},使得球 O2\htmlData{tutor-start=0,tutor-end=1}{O}_{\htmlData{tutor-start=3,tutor-end=4}{2}} 与球 O1\htmlData{tutor-start=0,tutor-end=1}{O}_{\htmlData{tutor-start=3,tutor-end=4}{1}}、圆台的下底面及侧面都只有一个公共点,除球 O2\htmlData{tutor-start=0,tutor-end=1}{O}_{\htmlData{tutor-start=3,tutor-end=4}{2}},圆台内最多还能放入半径为 3 的球的个数是( ) (A) 1 (B) 2 (C) 3 (D) 4

题解状态:标准答案与规范题解待补充

题目标签:FIRST-CHOICE-P6

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该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

7

一试 · 二、填空题(本题满分 54 分,每小题 9 分) · 组合数学

集合 {x1log1x10<12,xN}\{x \mid -1 \leqslant \log_{\frac{1}{x}} 10 < -\frac{1}{2}, x \in \mathbb{N}^*\} 的真子集的个数是 \_\_\_\_\_\_。

题解状态:标准答案与规范题解待补充

题目标签:FIRST-FILL-P1

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

8

一试 · 二、填空题(本题满分 54 分,每小题 9 分) · 平面几何

复平面上,非零复数 z1,z2\htmlData{tutor-start=0,tutor-end=1}{z}_{\htmlData{tutor-start=3,tutor-end=4}{1}}\htmlData{tutor-start=5,tutor-end=6}{,} \htmlData{tutor-start=7,tutor-end=8}{z}_{\htmlData{tutor-start=10,tutor-end=11}{2}} 在以 i\htmlData{tutor-start=0,tutor-end=1}{i} 为圆心,1 为半径的圆上,z1z2\overline{\htmlData{tutor-start=10,tutor-end=11}{z}_{\htmlData{tutor-start=13,tutor-end=14}{1}}} \htmlData{tutor-start=17,tutor-end=23}{\cdot }\htmlData{tutor-start=23,tutor-end=24}{z}_{\htmlData{tutor-start=26,tutor-end=27}{2}} 的实部为零,z1\htmlData{tutor-start=0,tutor-end=1}{z}_{\htmlData{tutor-start=3,tutor-end=4}{1}} 的辐角主值为 π6\frac{\htmlData{tutor-start=6,tutor-end=9}{\pi}}{\htmlData{tutor-start=11,tutor-end=12}{6}},则 z2=\htmlData{tutor-start=0,tutor-end=1}{z}_{\htmlData{tutor-start=3,tutor-end=4}{2}}\htmlData{tutor-start=5,tutor-end=6}{=}______.

题解状态:标准答案与规范题解待补充

题目标签:FIRST-FILL-P2

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该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

9

一试 · 二、填空题(本题满分 54 分,每小题 9 分) · 数学竞赛/待细分

曲线 C\htmlData{tutor-start=0,tutor-end=1}{C} 的极坐标方程是 ρ=1+cosθ\htmlData{tutor-start=0,tutor-end=4}{\rho}\htmlData{tutor-start=4,tutor-end=5}{=}\htmlData{tutor-start=5,tutor-end=6}{1}\htmlData{tutor-start=6,tutor-end=7}{+}\cos\htmlData{tutor-start=11,tutor-end=17}{\theta},点 A\htmlData{tutor-start=0,tutor-end=1}{A} 的极坐标是 (2,0)\htmlData{tutor-start=0,tutor-end=1}{(}\htmlData{tutor-start=1,tutor-end=2}{2}\htmlData{tutor-start=2,tutor-end=3}{,}\htmlData{tutor-start=3,tutor-end=4}{0}\htmlData{tutor-start=4,tutor-end=5}{)},曲线 C\htmlData{tutor-start=0,tutor-end=1}{C} 在它所在的平面内绕 A\htmlData{tutor-start=0,tutor-end=1}{A} 旋转一周,则它扫过的图形的面积是______.

题解状态:标准答案与规范题解待补充

题目标签:FIRST-FILL-P3

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该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

10

一试 · 二、填空题(本题满分 54 分,每小题 9 分) · 组合数学

已知将给定的两个全等的正三棱锥的底面粘在一起,恰得到一个所有二面角都相等的六面体,并且该六面体的最短棱的长为 2,则最远的两顶点间的距离是______.

题解状态:标准答案与规范题解待补充

题目标签:FIRST-FILL-P4

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

11

一试 · 二、填空题(本题满分 54 分,每小题 9 分) · 组合数学

从给定的六种不同颜色中选用若干种颜色,将一个正方体的六个面染色,每面恰染一种颜色,每两个具有公共棱的面染成不同的颜色。则不同的染色方法共有______种。(注:如果我们对两个相同的正方体染色后,可以通过适当的翻转,使得两个正方体的上、下、左、右、前、后六个对应面的染色都相同,那么,我们就说这两个正方体的染色方案相同。)

题解状态:标准答案与规范题解待补充

题目标签:FIRST-FILL-P5

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该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

12

一试 · 二、填空题(本题满分 54 分,每小题 9 分) · 平面几何

在直角坐标平面,以 (199,0)\htmlData{tutor-start=0,tutor-end=1}{(}\htmlData{tutor-start=1,tutor-end=2}{1}\htmlData{tutor-start=2,tutor-end=3}{9}\htmlData{tutor-start=3,tutor-end=4}{9}\htmlData{tutor-start=4,tutor-end=5}{,}\htmlData{tutor-start=5,tutor-end=6}{0}\htmlData{tutor-start=6,tutor-end=7}{)} 为圆心,199 为半径的圆周上整点(即横、纵坐标皆为整数的点)的个数为______.

题解状态:标准答案与规范题解待补充

题目标签:FIRST-FILL-P6

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该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

13

二试/加试 · 第二试 · 代数

(本题满分 25 分)设数列 {an}\htmlData{tutor-start=0,tutor-end=2}{\{}\htmlData{tutor-start=2,tutor-end=3}{a}_{\htmlData{tutor-start=5,tutor-end=6}{n}}\htmlData{tutor-start=7,tutor-end=9}{\}} 的前 n\htmlData{tutor-start=0,tutor-end=1}{n} 项和 Sn=2an1\htmlData{tutor-start=0,tutor-end=1}{S}_{\htmlData{tutor-start=3,tutor-end=4}{n}}\htmlData{tutor-start=5,tutor-end=6}{=}\htmlData{tutor-start=6,tutor-end=7}{2}\htmlData{tutor-start=7,tutor-end=8}{a}_{\htmlData{tutor-start=10,tutor-end=11}{n}}\htmlData{tutor-start=12,tutor-end=13}{-}\htmlData{tutor-start=13,tutor-end=14}{1} (n=1,2,\htmlData{tutor-start=0,tutor-end=1}{n}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=3}{1}\htmlData{tutor-start=3,tutor-end=4}{,} \htmlData{tutor-start=5,tutor-end=6}{2}\htmlData{tutor-start=6,tutor-end=7}{,} \cdots),数列 {bn}\htmlData{tutor-start=0,tutor-end=2}{\{}\htmlData{tutor-start=2,tutor-end=3}{b}_{\htmlData{tutor-start=5,tutor-end=6}{n}}\htmlData{tutor-start=7,tutor-end=9}{\}} 满足 b1=3\htmlData{tutor-start=0,tutor-end=1}{b}_{\htmlData{tutor-start=3,tutor-end=4}{1}}\htmlData{tutor-start=5,tutor-end=6}{=}\htmlData{tutor-start=6,tutor-end=7}{3}bk+1=ak+bk(k=1,2,)\htmlData{tutor-start=0,tutor-end=1}{b}_{\htmlData{tutor-start=3,tutor-end=4}{k}\htmlData{tutor-start=4,tutor-end=5}{+}\htmlData{tutor-start=5,tutor-end=6}{1}}\htmlData{tutor-start=7,tutor-end=8}{=}\htmlData{tutor-start=8,tutor-end=9}{a}_{\htmlData{tutor-start=11,tutor-end=12}{k}}\htmlData{tutor-start=13,tutor-end=14}{+}\htmlData{tutor-start=14,tutor-end=15}{b}_{\htmlData{tutor-start=17,tutor-end=18}{k}} \htmlData{tutor-start=20,tutor-end=21}{(}\htmlData{tutor-start=21,tutor-end=22}{k}\htmlData{tutor-start=22,tutor-end=23}{=}\htmlData{tutor-start=23,tutor-end=24}{1}\htmlData{tutor-start=24,tutor-end=25}{,} \htmlData{tutor-start=26,tutor-end=27}{2}\htmlData{tutor-start=27,tutor-end=28}{,} \cdots\htmlData{tutor-start=35,tutor-end=36}{)}。求数列 {bn}\htmlData{tutor-start=0,tutor-end=2}{\{}\htmlData{tutor-start=2,tutor-end=3}{b}_{\htmlData{tutor-start=5,tutor-end=6}{n}}\htmlData{tutor-start=7,tutor-end=9}{\}} 的前 n\htmlData{tutor-start=0,tutor-end=1}{n} 项和。

题解状态:标准答案与规范题解待补充

题目标签:SECOND-GENERAL-PROBLEM-P一

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

14

二试/加试 · 第二试 · 数学竞赛/待细分

(本题满分 25 分)求实数 a\htmlData{tutor-start=0,tutor-end=1}{a} 的取值范围,使得对任意实数 x\htmlData{tutor-start=0,tutor-end=1}{x} 和任意 θ[0,π2]\htmlData{tutor-start=0,tutor-end=7}{\theta }\htmlData{tutor-start=7,tutor-end=11}{\in }\htmlData{tutor-start=11,tutor-end=12}{[}\htmlData{tutor-start=12,tutor-end=13}{0}\htmlData{tutor-start=13,tutor-end=14}{,} \frac{\htmlData{tutor-start=21,tutor-end=24}{\pi}}{\htmlData{tutor-start=26,tutor-end=27}{2}}\htmlData{tutor-start=28,tutor-end=29}{]},恒有 (x+3+2sinθcosθ)2+(x+asinθ+acosθ)218\htmlData{tutor-start=0,tutor-end=1}{(}\htmlData{tutor-start=1,tutor-end=2}{x}\htmlData{tutor-start=2,tutor-end=3}{+}\htmlData{tutor-start=3,tutor-end=4}{3}\htmlData{tutor-start=4,tutor-end=5}{+}\htmlData{tutor-start=5,tutor-end=6}{2}\sin\htmlData{tutor-start=10,tutor-end=16}{\theta}\cos\htmlData{tutor-start=20,tutor-end=26}{\theta}\htmlData{tutor-start=26,tutor-end=27}{)}^{\htmlData{tutor-start=29,tutor-end=30}{2}}\htmlData{tutor-start=31,tutor-end=32}{+}\htmlData{tutor-start=32,tutor-end=33}{(}\htmlData{tutor-start=33,tutor-end=34}{x}\htmlData{tutor-start=34,tutor-end=35}{+}\htmlData{tutor-start=35,tutor-end=36}{a}\sin\htmlData{tutor-start=40,tutor-end=46}{\theta}\htmlData{tutor-start=46,tutor-end=47}{+}\htmlData{tutor-start=47,tutor-end=48}{a}\cos\htmlData{tutor-start=52,tutor-end=58}{\theta}\htmlData{tutor-start=58,tutor-end=59}{)}^{\htmlData{tutor-start=61,tutor-end=62}{2}} \htmlData{tutor-start=64,tutor-end=74}{\geqslant }\frac{\htmlData{tutor-start=80,tutor-end=81}{1}}{\htmlData{tutor-start=83,tutor-end=84}{8}}.

题解状态:标准答案与规范题解待补充

题目标签:SECOND-GENERAL-PROBLEM-P二

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

15

二试/加试 · 第二试 · 平面几何

(本题满分 35 分)如图,圆 O1\htmlData{tutor-start=0,tutor-end=1}{O}_{\htmlData{tutor-start=3,tutor-end=4}{1}} 和圆 O2\htmlData{tutor-start=0,tutor-end=1}{O}_{\htmlData{tutor-start=3,tutor-end=4}{2}}ABC\htmlData{tutor-start=0,tutor-end=10}{\triangle }\htmlData{tutor-start=10,tutor-end=11}{A}\htmlData{tutor-start=11,tutor-end=12}{B}\htmlData{tutor-start=12,tutor-end=13}{C} 的三边所在的三条直线都相切,E,F,G,H\htmlData{tutor-start=0,tutor-end=1}{E}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{F}\htmlData{tutor-start=4,tutor-end=5}{,} \htmlData{tutor-start=6,tutor-end=7}{G}\htmlData{tutor-start=7,tutor-end=8}{,} \htmlData{tutor-start=9,tutor-end=10}{H} 为切点,并且 EG,FH\htmlData{tutor-start=0,tutor-end=1}{E}\htmlData{tutor-start=1,tutor-end=2}{G}\htmlData{tutor-start=2,tutor-end=3}{,} \htmlData{tutor-start=4,tutor-end=5}{F}\htmlData{tutor-start=5,tutor-end=6}{H} 的延长线交于 P\htmlData{tutor-start=0,tutor-end=1}{P} 点。求证直线 PA\htmlData{tutor-start=0,tutor-end=1}{P}\htmlData{tutor-start=1,tutor-end=2}{A}BC\htmlData{tutor-start=0,tutor-end=1}{B}\htmlData{tutor-start=1,tutor-end=2}{C} 垂直。

原卷图示 1
原卷图示 1原卷第 3 页 · qwen3.7-plus_layout_detection · 需复核

题解状态:标准答案与规范题解待补充

题目标签:SECOND-GENERAL-PROBLEM-P三

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

16

二试/加试 · 第二试 · 数学竞赛/待细分

(本题满分 35 分)有 n(n6)\htmlData{tutor-start=0,tutor-end=1}{n}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{n} \htmlData{tutor-start=4,tutor-end=14}{\geqslant }\htmlData{tutor-start=14,tutor-end=15}{6}\htmlData{tutor-start=15,tutor-end=16}{)} 个人聚会,已知: (1)每人至少同其中 [n2]\left[ \frac{\htmlData{tutor-start=13,tutor-end=14}{n}}{\htmlData{tutor-start=16,tutor-end=17}{2}} \right] 个人互相认识; (2)对于其中任意 [n2]\left[ \frac{\htmlData{tutor-start=13,tutor-end=14}{n}}{\htmlData{tutor-start=16,tutor-end=17}{2}} \right] 个人,或者其中有 2 人相识,或者余下的人中有 2 人相识。 证明:这 n\htmlData{tutor-start=0,tutor-end=1}{n} 个人中必有三人两两认识。

题解状态:标准答案与规范题解待补充

题目标签:SECOND-GENERAL-PROBLEM-P四

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。