返回特征解读

2003 年全国高中数学联赛(学生版)

books/national_high_school_league_students/papers/competition-national-league-2003.pdf · HS-MATH-1024-v2.1-solution-aware

180 个小问/题组
1

一试 · 一、选择题(每小题 6 分,共 36 分) · 代数

(2003 年全国高中数学联赛)删去正整数数列 1,2,3,……中的所有完全平方数,得到一个新数列.这个数列的第 2003 项是 (A) 2046 (B) 2047 (C) 2048 (D) 2049

题解状态:标准答案与规范题解待补充

题目标签:FIRST-CHOICE-P1

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

2

一试 · 一、选择题(每小题 6 分,共 36 分) · 平面几何

a,bR\htmlData{tutor-start=0,tutor-end=1}{a}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{b} \htmlData{tutor-start=5,tutor-end=9}{\in }\mathbf{\htmlData{tutor-start=17,tutor-end=18}{R}}ab0\htmlData{tutor-start=0,tutor-end=1}{a}\htmlData{tutor-start=1,tutor-end=2}{b} \neq \htmlData{tutor-start=8,tutor-end=9}{0},那么直线 axy+b=0\htmlData{tutor-start=0,tutor-end=1}{a}\htmlData{tutor-start=1,tutor-end=2}{x}\htmlData{tutor-start=2,tutor-end=3}{-}\htmlData{tutor-start=3,tutor-end=4}{y}\htmlData{tutor-start=4,tutor-end=5}{+}\htmlData{tutor-start=5,tutor-end=6}{b}\htmlData{tutor-start=6,tutor-end=7}{=}\htmlData{tutor-start=7,tutor-end=8}{0} 和曲线 bx2+ay2=ab\htmlData{tutor-start=0,tutor-end=1}{b}\htmlData{tutor-start=1,tutor-end=2}{x}^{\htmlData{tutor-start=4,tutor-end=5}{2}}\htmlData{tutor-start=6,tutor-end=7}{+}\htmlData{tutor-start=7,tutor-end=8}{a}\htmlData{tutor-start=8,tutor-end=9}{y}^{\htmlData{tutor-start=11,tutor-end=12}{2}}\htmlData{tutor-start=13,tutor-end=14}{=}\htmlData{tutor-start=14,tutor-end=15}{a}\htmlData{tutor-start=15,tutor-end=16}{b} 的图形是

原卷图示 1
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原卷图示 2
原卷图示 2原卷第 1 页 · qwen3.7-plus_layout_detection · 需复核
原卷图示 3
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原卷图示 4
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题解状态:标准答案与规范题解待补充

题目标签:FIRST-CHOICE-P2

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

3

一试 · 一、选择题(每小题 6 分,共 36 分) · 平面几何

过抛物线 y2=8(x+2)\htmlData{tutor-start=0,tutor-end=1}{y}^{\htmlData{tutor-start=3,tutor-end=4}{2}}\htmlData{tutor-start=5,tutor-end=6}{=}\htmlData{tutor-start=6,tutor-end=7}{8}\htmlData{tutor-start=7,tutor-end=8}{(}\htmlData{tutor-start=8,tutor-end=9}{x}\htmlData{tutor-start=9,tutor-end=10}{+}\htmlData{tutor-start=10,tutor-end=11}{2}\htmlData{tutor-start=11,tutor-end=12}{)} 的焦点 F\htmlData{tutor-start=0,tutor-end=1}{F} 作倾斜角为 6060^\circ 的直线,若此直线与抛物线交于 A\htmlData{tutor-start=0,tutor-end=1}{A}B\htmlData{tutor-start=0,tutor-end=1}{B} 两点,弦 AB\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{B} 的中垂线与 x\htmlData{tutor-start=0,tutor-end=1}{x} 轴交于点 P\htmlData{tutor-start=0,tutor-end=1}{P},则线段 PF\htmlData{tutor-start=0,tutor-end=1}{P}\htmlData{tutor-start=1,tutor-end=2}{F} 的长等于 (A) 163\frac{\htmlData{tutor-start=6,tutor-end=7}{1}\htmlData{tutor-start=7,tutor-end=8}{6}}{\htmlData{tutor-start=10,tutor-end=11}{3}} (B) 83\frac{\htmlData{tutor-start=6,tutor-end=7}{8}}{\htmlData{tutor-start=9,tutor-end=10}{3}} (C) 1633\frac{\htmlData{tutor-start=6,tutor-end=7}{1}\htmlData{tutor-start=7,tutor-end=8}{6}}{\htmlData{tutor-start=10,tutor-end=11}{3}}\sqrt{\htmlData{tutor-start=18,tutor-end=19}{3}} (D) 83\htmlData{tutor-start=0,tutor-end=1}{8}\sqrt{\htmlData{tutor-start=7,tutor-end=8}{3}}

题解状态:标准答案与规范题解待补充

题目标签:FIRST-CHOICE-P3

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

4

一试 · 一、选择题(每小题 6 分,共 36 分) · 数学竞赛/待细分

x[5π12,π3]\htmlData{tutor-start=0,tutor-end=1}{x} \htmlData{tutor-start=2,tutor-end=6}{\in }\htmlData{tutor-start=6,tutor-end=7}{[}\htmlData{tutor-start=7,tutor-end=8}{-}\frac{\htmlData{tutor-start=14,tutor-end=15}{5}\htmlData{tutor-start=15,tutor-end=18}{\pi}}{\htmlData{tutor-start=20,tutor-end=21}{1}\htmlData{tutor-start=21,tutor-end=22}{2}}\htmlData{tutor-start=23,tutor-end=24}{,} \htmlData{tutor-start=25,tutor-end=26}{-}\frac{\htmlData{tutor-start=32,tutor-end=35}{\pi}}{\htmlData{tutor-start=37,tutor-end=38}{3}}\htmlData{tutor-start=39,tutor-end=40}{]},则 y=tan(x+2π3)tan(x+π6)+cos(x+π6)\htmlData{tutor-start=0,tutor-end=1}{y}\htmlData{tutor-start=1,tutor-end=2}{=}\tan\htmlData{tutor-start=6,tutor-end=7}{(}\htmlData{tutor-start=7,tutor-end=8}{x}\htmlData{tutor-start=8,tutor-end=9}{+}\frac{\htmlData{tutor-start=15,tutor-end=16}{2}\htmlData{tutor-start=16,tutor-end=19}{\pi}}{\htmlData{tutor-start=21,tutor-end=22}{3}}\htmlData{tutor-start=23,tutor-end=24}{)}\htmlData{tutor-start=24,tutor-end=25}{-}\tan\htmlData{tutor-start=29,tutor-end=30}{(}\htmlData{tutor-start=30,tutor-end=31}{x}\htmlData{tutor-start=31,tutor-end=32}{+}\frac{\htmlData{tutor-start=38,tutor-end=41}{\pi}}{\htmlData{tutor-start=43,tutor-end=44}{6}}\htmlData{tutor-start=45,tutor-end=46}{)}\htmlData{tutor-start=46,tutor-end=47}{+}\cos\htmlData{tutor-start=51,tutor-end=52}{(}\htmlData{tutor-start=52,tutor-end=53}{x}\htmlData{tutor-start=53,tutor-end=54}{+}\frac{\htmlData{tutor-start=60,tutor-end=63}{\pi}}{\htmlData{tutor-start=65,tutor-end=66}{6}}\htmlData{tutor-start=67,tutor-end=68}{)} 的最大值是 (A) 1252\frac{\htmlData{tutor-start=6,tutor-end=7}{1}\htmlData{tutor-start=7,tutor-end=8}{2}}{\htmlData{tutor-start=10,tutor-end=11}{5}}\sqrt{\htmlData{tutor-start=18,tutor-end=19}{2}} (B) 1162\frac{\htmlData{tutor-start=6,tutor-end=7}{1}\htmlData{tutor-start=7,tutor-end=8}{1}}{\htmlData{tutor-start=10,tutor-end=11}{6}}\sqrt{\htmlData{tutor-start=18,tutor-end=19}{2}} (C) 1163\frac{\htmlData{tutor-start=6,tutor-end=7}{1}\htmlData{tutor-start=7,tutor-end=8}{1}}{\htmlData{tutor-start=10,tutor-end=11}{6}}\sqrt{\htmlData{tutor-start=18,tutor-end=19}{3}} (D) 1253\frac{\htmlData{tutor-start=6,tutor-end=7}{1}\htmlData{tutor-start=7,tutor-end=8}{2}}{\htmlData{tutor-start=10,tutor-end=11}{5}}\sqrt{\htmlData{tutor-start=18,tutor-end=19}{3}}

题解状态:标准答案与规范题解待补充

题目标签:FIRST-CHOICE-P4

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

5

一试 · 一、选择题(每小题 6 分,共 36 分) · 代数

已知 x,y\htmlData{tutor-start=0,tutor-end=1}{x}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{y} 都在区间 (2,2)\htmlData{tutor-start=0,tutor-end=1}{(}\htmlData{tutor-start=1,tutor-end=2}{-}\htmlData{tutor-start=2,tutor-end=3}{2}\htmlData{tutor-start=3,tutor-end=4}{,} \htmlData{tutor-start=5,tutor-end=6}{2}\htmlData{tutor-start=6,tutor-end=7}{)} 内,且 xy=1\htmlData{tutor-start=0,tutor-end=1}{x}\htmlData{tutor-start=1,tutor-end=2}{y}\htmlData{tutor-start=2,tutor-end=3}{=}\htmlData{tutor-start=3,tutor-end=4}{-}\htmlData{tutor-start=4,tutor-end=5}{1},则函数 u=44x2+99y2\htmlData{tutor-start=0,tutor-end=1}{u}\htmlData{tutor-start=1,tutor-end=2}{=}\frac{\htmlData{tutor-start=8,tutor-end=9}{4}}{\htmlData{tutor-start=11,tutor-end=12}{4}\htmlData{tutor-start=12,tutor-end=13}{-}\htmlData{tutor-start=13,tutor-end=14}{x}^{\htmlData{tutor-start=16,tutor-end=17}{2}}}\htmlData{tutor-start=19,tutor-end=20}{+}\frac{\htmlData{tutor-start=26,tutor-end=27}{9}}{\htmlData{tutor-start=29,tutor-end=30}{9}\htmlData{tutor-start=30,tutor-end=31}{-}\htmlData{tutor-start=31,tutor-end=32}{y}^{\htmlData{tutor-start=34,tutor-end=35}{2}}} 的最小值是 (A) 85\frac{\htmlData{tutor-start=6,tutor-end=7}{8}}{\htmlData{tutor-start=9,tutor-end=10}{5}} (B) 2411\frac{\htmlData{tutor-start=6,tutor-end=7}{2}\htmlData{tutor-start=7,tutor-end=8}{4}}{\htmlData{tutor-start=10,tutor-end=11}{1}\htmlData{tutor-start=11,tutor-end=12}{1}} (C) 127\frac{\htmlData{tutor-start=6,tutor-end=7}{1}\htmlData{tutor-start=7,tutor-end=8}{2}}{\htmlData{tutor-start=10,tutor-end=11}{7}} (D) 125\frac{\htmlData{tutor-start=6,tutor-end=7}{1}\htmlData{tutor-start=7,tutor-end=8}{2}}{\htmlData{tutor-start=10,tutor-end=11}{5}}

题解状态:标准答案与规范题解待补充

题目标签:FIRST-CHOICE-P5

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

6

一试 · 一、选择题(每小题 6 分,共 36 分) · 平面几何

在四面体 ABCD\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{B}\htmlData{tutor-start=2,tutor-end=3}{C}\htmlData{tutor-start=3,tutor-end=4}{D} 中,设 AB=1\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{B}\htmlData{tutor-start=2,tutor-end=3}{=}\htmlData{tutor-start=3,tutor-end=4}{1}CD=3\htmlData{tutor-start=0,tutor-end=1}{C}\htmlData{tutor-start=1,tutor-end=2}{D}\htmlData{tutor-start=2,tutor-end=3}{=}\sqrt{\htmlData{tutor-start=9,tutor-end=10}{3}},直线 AB\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{B}CD\htmlData{tutor-start=0,tutor-end=1}{C}\htmlData{tutor-start=1,tutor-end=2}{D} 的距离为 2,夹角为 π3\frac{\htmlData{tutor-start=6,tutor-end=9}{\pi}}{\htmlData{tutor-start=11,tutor-end=12}{3}},则四面体 ABCD\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{B}\htmlData{tutor-start=2,tutor-end=3}{C}\htmlData{tutor-start=3,tutor-end=4}{D} 的体积等于 (A) 32\frac{\sqrt{\htmlData{tutor-start=12,tutor-end=13}{3}}}{\htmlData{tutor-start=16,tutor-end=17}{2}} (B) 12\frac{\htmlData{tutor-start=6,tutor-end=7}{1}}{\htmlData{tutor-start=9,tutor-end=10}{2}} (C) 13\frac{\htmlData{tutor-start=6,tutor-end=7}{1}}{\htmlData{tutor-start=9,tutor-end=10}{3}} (D) 33\frac{\sqrt{\htmlData{tutor-start=12,tutor-end=13}{3}}}{\htmlData{tutor-start=16,tutor-end=17}{3}}

题解状态:标准答案与规范题解待补充

题目标签:FIRST-CHOICE-P6

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

7

一试 · 二、填空题(每小题 9 分,共 54 分) · 代数

不等式 x32x24x+3<0\htmlData{tutor-start=0,tutor-end=1}{|}\htmlData{tutor-start=1,tutor-end=2}{x}\htmlData{tutor-start=2,tutor-end=3}{|}^{\htmlData{tutor-start=5,tutor-end=6}{3}}\htmlData{tutor-start=7,tutor-end=8}{-}\htmlData{tutor-start=8,tutor-end=9}{2}\htmlData{tutor-start=9,tutor-end=10}{x}^{\htmlData{tutor-start=12,tutor-end=13}{2}}\htmlData{tutor-start=14,tutor-end=15}{-}\htmlData{tutor-start=15,tutor-end=16}{4}\htmlData{tutor-start=16,tutor-end=17}{|}\htmlData{tutor-start=17,tutor-end=18}{x}\htmlData{tutor-start=18,tutor-end=19}{|}\htmlData{tutor-start=19,tutor-end=20}{+}\htmlData{tutor-start=20,tutor-end=21}{3}\htmlData{tutor-start=21,tutor-end=22}{<}\htmlData{tutor-start=22,tutor-end=23}{0} 的解集是____________________.

题解状态:标准答案与规范题解待补充

题目标签:FIRST-FILL-P7

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

8

一试 · 二、填空题(每小题 9 分,共 54 分) · 平面几何

F1\htmlData{tutor-start=0,tutor-end=1}{F}_{\htmlData{tutor-start=3,tutor-end=4}{1}}F2\htmlData{tutor-start=0,tutor-end=1}{F}_{\htmlData{tutor-start=3,tutor-end=4}{2}} 是椭圆 x29+y24=1\frac{\htmlData{tutor-start=6,tutor-end=7}{x}^{\htmlData{tutor-start=9,tutor-end=10}{2}}}{\htmlData{tutor-start=13,tutor-end=14}{9}}\htmlData{tutor-start=15,tutor-end=16}{+}\frac{\htmlData{tutor-start=22,tutor-end=23}{y}^{\htmlData{tutor-start=25,tutor-end=26}{2}}}{\htmlData{tutor-start=29,tutor-end=30}{4}}\htmlData{tutor-start=31,tutor-end=32}{=}\htmlData{tutor-start=32,tutor-end=33}{1} 的两个焦点,P\htmlData{tutor-start=0,tutor-end=1}{P} 是椭圆上一点,且 PF1:PF2=2:1\htmlData{tutor-start=0,tutor-end=1}{|}\htmlData{tutor-start=1,tutor-end=2}{P}\htmlData{tutor-start=2,tutor-end=3}{F}_{\htmlData{tutor-start=5,tutor-end=6}{1}}\htmlData{tutor-start=7,tutor-end=8}{|}\htmlData{tutor-start=8,tutor-end=9}{:}\htmlData{tutor-start=9,tutor-end=10}{|}\htmlData{tutor-start=10,tutor-end=11}{P}\htmlData{tutor-start=11,tutor-end=12}{F}_{\htmlData{tutor-start=14,tutor-end=15}{2}}\htmlData{tutor-start=16,tutor-end=17}{|}\htmlData{tutor-start=17,tutor-end=18}{=}\htmlData{tutor-start=18,tutor-end=19}{2}\htmlData{tutor-start=19,tutor-end=20}{:}\htmlData{tutor-start=20,tutor-end=21}{1},则 PF1F2\htmlData{tutor-start=0,tutor-end=10}{\triangle }\htmlData{tutor-start=10,tutor-end=11}{P}\htmlData{tutor-start=11,tutor-end=12}{F}_{\htmlData{tutor-start=14,tutor-end=15}{1}}\htmlData{tutor-start=16,tutor-end=17}{F}_{\htmlData{tutor-start=19,tutor-end=20}{2}} 的面积等于____________________.

题解状态:标准答案与规范题解待补充

题目标签:FIRST-FILL-P8

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

9

一试 · 二、填空题(每小题 9 分,共 54 分) · 组合数学

已知 A={xx24x+3<0,xR}\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=4}{\{}\htmlData{tutor-start=4,tutor-end=5}{x} \htmlData{tutor-start=6,tutor-end=11}{\mid }\htmlData{tutor-start=11,tutor-end=12}{x}^{\htmlData{tutor-start=14,tutor-end=15}{2}}\htmlData{tutor-start=16,tutor-end=17}{-}\htmlData{tutor-start=17,tutor-end=18}{4}\htmlData{tutor-start=18,tutor-end=19}{x}\htmlData{tutor-start=19,tutor-end=20}{+}\htmlData{tutor-start=20,tutor-end=21}{3}\htmlData{tutor-start=21,tutor-end=22}{<}\htmlData{tutor-start=22,tutor-end=23}{0}\htmlData{tutor-start=23,tutor-end=24}{,} \htmlData{tutor-start=25,tutor-end=26}{x} \htmlData{tutor-start=27,tutor-end=31}{\in }\mathbf{\htmlData{tutor-start=39,tutor-end=40}{R}}\htmlData{tutor-start=41,tutor-end=43}{\}}B={x21x+a0,x22(a+7)x+50,xR}\htmlData{tutor-start=0,tutor-end=1}{B}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=4}{\{}\htmlData{tutor-start=4,tutor-end=5}{x} \htmlData{tutor-start=6,tutor-end=11}{\mid }\htmlData{tutor-start=11,tutor-end=12}{2}^{\htmlData{tutor-start=14,tutor-end=15}{1}\htmlData{tutor-start=15,tutor-end=16}{-}\htmlData{tutor-start=16,tutor-end=17}{x}}\htmlData{tutor-start=18,tutor-end=19}{+}\htmlData{tutor-start=19,tutor-end=20}{a} \htmlData{tutor-start=21,tutor-end=31}{\leqslant }\htmlData{tutor-start=31,tutor-end=32}{0}\htmlData{tutor-start=32,tutor-end=33}{,} \htmlData{tutor-start=34,tutor-end=35}{x}^{\htmlData{tutor-start=37,tutor-end=38}{2}}\htmlData{tutor-start=39,tutor-end=40}{-}\htmlData{tutor-start=40,tutor-end=41}{2}\htmlData{tutor-start=41,tutor-end=42}{(}\htmlData{tutor-start=42,tutor-end=43}{a}\htmlData{tutor-start=43,tutor-end=44}{+}\htmlData{tutor-start=44,tutor-end=45}{7}\htmlData{tutor-start=45,tutor-end=46}{)}\htmlData{tutor-start=46,tutor-end=47}{x}\htmlData{tutor-start=47,tutor-end=48}{+}\htmlData{tutor-start=48,tutor-end=49}{5} \htmlData{tutor-start=50,tutor-end=60}{\leqslant }\htmlData{tutor-start=60,tutor-end=61}{0}\htmlData{tutor-start=61,tutor-end=62}{,} \htmlData{tutor-start=63,tutor-end=64}{x} \htmlData{tutor-start=65,tutor-end=69}{\in }\mathbf{\htmlData{tutor-start=77,tutor-end=78}{R}}\htmlData{tutor-start=79,tutor-end=81}{\}}AB\htmlData{tutor-start=0,tutor-end=1}{A} \htmlData{tutor-start=2,tutor-end=12}{\subseteq }\htmlData{tutor-start=12,tutor-end=13}{B},则实数 a\htmlData{tutor-start=0,tutor-end=1}{a} 的取值范围是____________________.

题解状态:标准答案与规范题解待补充

题目标签:FIRST-FILL-P9

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

10

一试 · 二、填空题(每小题 9 分,共 54 分) · 数论

已知 a,b,c,d\htmlData{tutor-start=0,tutor-end=1}{a}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{b}\htmlData{tutor-start=4,tutor-end=5}{,} \htmlData{tutor-start=6,tutor-end=7}{c}\htmlData{tutor-start=7,tutor-end=8}{,} \htmlData{tutor-start=9,tutor-end=10}{d} 均为正整数,且 logab=32,logcd=54\log_{\htmlData{tutor-start=6,tutor-end=7}{a}} \htmlData{tutor-start=9,tutor-end=10}{b}\htmlData{tutor-start=10,tutor-end=11}{=}\frac{\htmlData{tutor-start=17,tutor-end=18}{3}}{\htmlData{tutor-start=20,tutor-end=21}{2}}\htmlData{tutor-start=22,tutor-end=23}{,} \log_{\htmlData{tutor-start=30,tutor-end=31}{c}} \htmlData{tutor-start=33,tutor-end=34}{d}\htmlData{tutor-start=34,tutor-end=35}{=}\frac{\htmlData{tutor-start=41,tutor-end=42}{5}}{\htmlData{tutor-start=44,tutor-end=45}{4}},若 ac=9\htmlData{tutor-start=0,tutor-end=1}{a}\htmlData{tutor-start=1,tutor-end=2}{-}\htmlData{tutor-start=2,tutor-end=3}{c}\htmlData{tutor-start=3,tutor-end=4}{=}\htmlData{tutor-start=4,tutor-end=5}{9},则 bd=\htmlData{tutor-start=0,tutor-end=1}{b}\htmlData{tutor-start=1,tutor-end=2}{-}\htmlData{tutor-start=2,tutor-end=3}{d}\htmlData{tutor-start=3,tutor-end=4}{=}\underline{\hspace{3cm}}.

题解状态:标准答案与规范题解待补充

题目标签:FIRST-FILL-P10

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

11

一试 · 二、填空题(每小题 9 分,共 54 分) · 平面几何

将八个半径都为 1 的球分放两层放置在一个圆柱内,并使得每个球都和其相邻的四个球相切,且与圆柱的一个底面及侧面都相切,则此圆柱的高等于\underline{\hspace{3cm}}.

题解状态:标准答案与规范题解待补充

题目标签:FIRST-FILL-P11

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

12

一试 · 二、填空题(每小题 9 分,共 54 分) · 数学竞赛/待细分

Mn={(十进制) n 位纯小数 0.a1a2anai 只取 0 或 1(i=1,2,,n1),an=1}\htmlData{tutor-start=0,tutor-end=1}{M}_{\htmlData{tutor-start=3,tutor-end=4}{n}}\htmlData{tutor-start=5,tutor-end=6}{=}\htmlData{tutor-start=6,tutor-end=8}{\{}\text{\htmlData{tutor-start=14,tutor-end=15}{(}\htmlData{tutor-start=15,tutor-end=16}{十}\htmlData{tutor-start=16,tutor-end=17}{进}\htmlData{tutor-start=17,tutor-end=18}{制}\htmlData{tutor-start=18,tutor-end=19}{)} } \htmlData{tutor-start=22,tutor-end=23}{n} \text{ \htmlData{tutor-start=31,tutor-end=32}{位}\htmlData{tutor-start=32,tutor-end=33}{纯}\htmlData{tutor-start=33,tutor-end=34}{小}\htmlData{tutor-start=34,tutor-end=35}{数} } \htmlData{tutor-start=38,tutor-end=39}{0}\htmlData{tutor-start=39,tutor-end=40}{.}\overline{\htmlData{tutor-start=50,tutor-end=51}{a}_{\htmlData{tutor-start=53,tutor-end=54}{1}} \htmlData{tutor-start=56,tutor-end=57}{a}_{\htmlData{tutor-start=59,tutor-end=60}{2}} \cdots \htmlData{tutor-start=69,tutor-end=70}{a}_{\htmlData{tutor-start=72,tutor-end=73}{n}}} \htmlData{tutor-start=76,tutor-end=81}{\mid }\htmlData{tutor-start=81,tutor-end=82}{a}_{\htmlData{tutor-start=84,tutor-end=85}{i}} \text{ \htmlData{tutor-start=94,tutor-end=95}{只}\htmlData{tutor-start=95,tutor-end=96}{取} } \htmlData{tutor-start=99,tutor-end=100}{0} \text{ \htmlData{tutor-start=108,tutor-end=109}{或} } \htmlData{tutor-start=112,tutor-end=113}{1} \htmlData{tutor-start=114,tutor-end=115}{(}\htmlData{tutor-start=115,tutor-end=116}{i}\htmlData{tutor-start=116,tutor-end=117}{=}\htmlData{tutor-start=117,tutor-end=118}{1}\htmlData{tutor-start=118,tutor-end=119}{,} \htmlData{tutor-start=120,tutor-end=121}{2}\htmlData{tutor-start=121,tutor-end=122}{,} \cdots\htmlData{tutor-start=129,tutor-end=130}{,} \htmlData{tutor-start=131,tutor-end=132}{n}\htmlData{tutor-start=132,tutor-end=133}{-}\htmlData{tutor-start=133,tutor-end=134}{1}\htmlData{tutor-start=134,tutor-end=135}{)}\htmlData{tutor-start=135,tutor-end=136}{,} \htmlData{tutor-start=137,tutor-end=138}{a}_{\htmlData{tutor-start=140,tutor-end=141}{n}}\htmlData{tutor-start=142,tutor-end=143}{=}\htmlData{tutor-start=143,tutor-end=144}{1}\htmlData{tutor-start=144,tutor-end=146}{\}}Tn\htmlData{tutor-start=0,tutor-end=1}{T}_{\htmlData{tutor-start=3,tutor-end=4}{n}}Mn\htmlData{tutor-start=0,tutor-end=1}{M}_{\htmlData{tutor-start=3,tutor-end=4}{n}} 中元素的个数,Sn\htmlData{tutor-start=0,tutor-end=1}{S}_{\htmlData{tutor-start=3,tutor-end=4}{n}}Mn\htmlData{tutor-start=0,tutor-end=1}{M}_{\htmlData{tutor-start=3,tutor-end=4}{n}} 中所有元素的和,则 limnSnTn=\lim_{\htmlData{tutor-start=6,tutor-end=7}{n} \htmlData{tutor-start=8,tutor-end=12}{\to }\htmlData{tutor-start=12,tutor-end=18}{\infty}} \frac{\htmlData{tutor-start=26,tutor-end=27}{S}_{\htmlData{tutor-start=29,tutor-end=30}{n}}}{\htmlData{tutor-start=33,tutor-end=34}{T}_{\htmlData{tutor-start=36,tutor-end=37}{n}}} \htmlData{tutor-start=40,tutor-end=41}{=}\underline{\hspace{3cm}}.

题解状态:标准答案与规范题解待补充

题目标签:FIRST-FILL-P12

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

13

一试 · 三、(本题满分 20 分) · 代数

32x5\frac{\htmlData{tutor-start=6,tutor-end=7}{3}}{\htmlData{tutor-start=9,tutor-end=10}{2}} \htmlData{tutor-start=12,tutor-end=22}{\leqslant }\htmlData{tutor-start=22,tutor-end=23}{x} \htmlData{tutor-start=24,tutor-end=34}{\leqslant }\htmlData{tutor-start=34,tutor-end=35}{5},证明不等式 2x+1+2x3+153x<219\htmlData{tutor-start=0,tutor-end=1}{2}\sqrt{\htmlData{tutor-start=7,tutor-end=8}{x}\htmlData{tutor-start=8,tutor-end=9}{+}\htmlData{tutor-start=9,tutor-end=10}{1}}\htmlData{tutor-start=11,tutor-end=12}{+}\sqrt{\htmlData{tutor-start=18,tutor-end=19}{2}\htmlData{tutor-start=19,tutor-end=20}{x}\htmlData{tutor-start=20,tutor-end=21}{-}\htmlData{tutor-start=21,tutor-end=22}{3}}\htmlData{tutor-start=23,tutor-end=24}{+}\sqrt{\htmlData{tutor-start=30,tutor-end=31}{1}\htmlData{tutor-start=31,tutor-end=32}{5}\htmlData{tutor-start=32,tutor-end=33}{-}\htmlData{tutor-start=33,tutor-end=34}{3}\htmlData{tutor-start=34,tutor-end=35}{x}}\htmlData{tutor-start=36,tutor-end=37}{<}\htmlData{tutor-start=37,tutor-end=38}{2}\sqrt{\htmlData{tutor-start=44,tutor-end=45}{1}\htmlData{tutor-start=45,tutor-end=46}{9}}.

题解状态:标准答案与规范题解待补充

题目标签:FIRST-SOLUTION-P13

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

14

一试 · 四、(本题满分 20 分) · 平面几何

A,B,C\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{B}\htmlData{tutor-start=4,tutor-end=5}{,} \htmlData{tutor-start=6,tutor-end=7}{C} 分别是复数 Z0=ai,Z1=12+bi,Z2=1+ci\htmlData{tutor-start=0,tutor-end=1}{Z}_{\htmlData{tutor-start=3,tutor-end=4}{0}}\htmlData{tutor-start=5,tutor-end=6}{=}\htmlData{tutor-start=6,tutor-end=7}{a}\htmlData{tutor-start=7,tutor-end=8}{i}\htmlData{tutor-start=8,tutor-end=9}{,} \htmlData{tutor-start=10,tutor-end=11}{Z}_{\htmlData{tutor-start=13,tutor-end=14}{1}}\htmlData{tutor-start=15,tutor-end=16}{=}\frac{\htmlData{tutor-start=22,tutor-end=23}{1}}{\htmlData{tutor-start=25,tutor-end=26}{2}}\htmlData{tutor-start=27,tutor-end=28}{+}\htmlData{tutor-start=28,tutor-end=29}{b}\htmlData{tutor-start=29,tutor-end=30}{i}\htmlData{tutor-start=30,tutor-end=31}{,} \htmlData{tutor-start=32,tutor-end=33}{Z}_{\htmlData{tutor-start=35,tutor-end=36}{2}}\htmlData{tutor-start=37,tutor-end=38}{=}\htmlData{tutor-start=38,tutor-end=39}{1}\htmlData{tutor-start=39,tutor-end=40}{+}\htmlData{tutor-start=40,tutor-end=41}{c}\htmlData{tutor-start=41,tutor-end=42}{i} (其中 a,b,c\htmlData{tutor-start=0,tutor-end=1}{a}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{b}\htmlData{tutor-start=4,tutor-end=5}{,} \htmlData{tutor-start=6,tutor-end=7}{c} 都是实数) 对应的不共线的三点. 证明:曲线 Z=Z0cos4t+2Z1cos2tsin2t+Z2sin4t(tR)\htmlData{tutor-start=0,tutor-end=1}{Z}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=3}{Z}_{\htmlData{tutor-start=5,tutor-end=6}{0}} \cos^{\htmlData{tutor-start=14,tutor-end=15}{4}} \htmlData{tutor-start=17,tutor-end=18}{t}\htmlData{tutor-start=18,tutor-end=19}{+}\htmlData{tutor-start=19,tutor-end=20}{2}\htmlData{tutor-start=20,tutor-end=21}{Z}_{\htmlData{tutor-start=23,tutor-end=24}{1}} \cos^{\htmlData{tutor-start=32,tutor-end=33}{2}} \htmlData{tutor-start=35,tutor-end=36}{t} \sin^{\htmlData{tutor-start=43,tutor-end=44}{2}} \htmlData{tutor-start=46,tutor-end=47}{t}\htmlData{tutor-start=47,tutor-end=48}{+}\htmlData{tutor-start=48,tutor-end=49}{Z}_{\htmlData{tutor-start=51,tutor-end=52}{2}} \sin^{\htmlData{tutor-start=60,tutor-end=61}{4}} \htmlData{tutor-start=63,tutor-end=64}{t} \quad \htmlData{tutor-start=71,tutor-end=72}{(}\htmlData{tutor-start=72,tutor-end=73}{t} \htmlData{tutor-start=74,tutor-end=78}{\in }\mathbf{\htmlData{tutor-start=86,tutor-end=87}{R}}\htmlData{tutor-start=88,tutor-end=89}{)}ABC\htmlData{tutor-start=0,tutor-end=10}{\triangle }\htmlData{tutor-start=10,tutor-end=11}{A}\htmlData{tutor-start=11,tutor-end=12}{B}\htmlData{tutor-start=12,tutor-end=13}{C} 中平行于 AC\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{C} 的中位线只有一个公共点,并求出此点.

题解状态:标准答案与规范题解待补充

题目标签:FIRST-SOLUTION-P14

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

15

一试 · 五、(本题满分 20 分) · 平面几何

一张纸上画有一个半径为 R\htmlData{tutor-start=0,tutor-end=1}{R} 的圆 O\htmlData{tutor-start=0,tutor-end=1}{O} 和圆内一个定点 A\htmlData{tutor-start=0,tutor-end=1}{A},且 OA=a\htmlData{tutor-start=0,tutor-end=1}{O}\htmlData{tutor-start=1,tutor-end=2}{A}\htmlData{tutor-start=2,tutor-end=3}{=}\htmlData{tutor-start=3,tutor-end=4}{a},折叠纸片,使圆周上某一点 A\htmlData{tutor-start=0,tutor-end=1}{A}' 刚好与点 A\htmlData{tutor-start=0,tutor-end=1}{A} 重合. 这样的每一种折法,都留下一条折痕. 当 A\htmlData{tutor-start=0,tutor-end=1}{A}' 取遍圆周上所有点时,求所有折痕所在直线上点的集合.

题解状态:标准答案与规范题解待补充

题目标签:FIRST-SOLUTION-P15

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

16

二试/加试 · 加试题 · 平面几何

(本题 50 分) 过圆外一点 P\htmlData{tutor-start=0,tutor-end=1}{P} 作圆的两条切线和一条割线,切点为 A\htmlData{tutor-start=0,tutor-end=1}{A}B\htmlData{tutor-start=0,tutor-end=1}{B},所作割线交圆于 C\htmlData{tutor-start=0,tutor-end=1}{C}D\htmlData{tutor-start=0,tutor-end=1}{D} 两点,C\htmlData{tutor-start=0,tutor-end=1}{C}P\htmlData{tutor-start=0,tutor-end=1}{P}D\htmlData{tutor-start=0,tutor-end=1}{D} 之间。在弦 CD\htmlData{tutor-start=0,tutor-end=1}{C}\htmlData{tutor-start=1,tutor-end=2}{D} 上取一点 Q\htmlData{tutor-start=0,tutor-end=1}{Q},使 DAQ=PBC\htmlData{tutor-start=0,tutor-end=7}{\angle }\htmlData{tutor-start=7,tutor-end=8}{D}\htmlData{tutor-start=8,tutor-end=9}{A}\htmlData{tutor-start=9,tutor-end=10}{Q}\htmlData{tutor-start=10,tutor-end=11}{=}\htmlData{tutor-start=11,tutor-end=18}{\angle }\htmlData{tutor-start=18,tutor-end=19}{P}\htmlData{tutor-start=19,tutor-end=20}{B}\htmlData{tutor-start=20,tutor-end=21}{C}。 求证:DBQ=PAC\htmlData{tutor-start=0,tutor-end=7}{\angle }\htmlData{tutor-start=7,tutor-end=8}{D}\htmlData{tutor-start=8,tutor-end=9}{B}\htmlData{tutor-start=9,tutor-end=10}{Q}\htmlData{tutor-start=10,tutor-end=11}{=}\htmlData{tutor-start=11,tutor-end=18}{\angle }\htmlData{tutor-start=18,tutor-end=19}{P}\htmlData{tutor-start=19,tutor-end=20}{A}\htmlData{tutor-start=20,tutor-end=21}{C}

题解状态:标准答案与规范题解待补充

题目标签:SECOND-GENERAL-PROBLEM-P一

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

17

二试/加试 · 加试题 · 平面几何

(本题 50 分) 设三角形的三边长分别是正整数 l\htmlData{tutor-start=0,tutor-end=1}{l}m\htmlData{tutor-start=0,tutor-end=1}{m}n\htmlData{tutor-start=0,tutor-end=1}{n}。且 l>m>n>0\htmlData{tutor-start=0,tutor-end=1}{l}\htmlData{tutor-start=1,tutor-end=2}{>}\htmlData{tutor-start=2,tutor-end=3}{m}\htmlData{tutor-start=3,tutor-end=4}{>}\htmlData{tutor-start=4,tutor-end=5}{n}\htmlData{tutor-start=5,tutor-end=6}{>}\htmlData{tutor-start=6,tutor-end=7}{0}。 已知 {3l104}={3m104}={3n104}\left\{\frac{\htmlData{tutor-start=13,tutor-end=14}{3}^{\htmlData{tutor-start=16,tutor-end=17}{l}}}{\htmlData{tutor-start=20,tutor-end=21}{1}\htmlData{tutor-start=21,tutor-end=22}{0}^{\htmlData{tutor-start=24,tutor-end=25}{4}}}\right\}\htmlData{tutor-start=35,tutor-end=36}{=}\left\{\frac{\htmlData{tutor-start=49,tutor-end=50}{3}^{\htmlData{tutor-start=52,tutor-end=53}{m}}}{\htmlData{tutor-start=56,tutor-end=57}{1}\htmlData{tutor-start=57,tutor-end=58}{0}^{\htmlData{tutor-start=60,tutor-end=61}{4}}}\right\}\htmlData{tutor-start=71,tutor-end=72}{=}\left\{\frac{\htmlData{tutor-start=85,tutor-end=86}{3}^{\htmlData{tutor-start=88,tutor-end=89}{n}}}{\htmlData{tutor-start=92,tutor-end=93}{1}\htmlData{tutor-start=93,tutor-end=94}{0}^{\htmlData{tutor-start=96,tutor-end=97}{4}}}\right\},其中 {x}=x[x]\htmlData{tutor-start=0,tutor-end=2}{\{}\htmlData{tutor-start=2,tutor-end=3}{x}\htmlData{tutor-start=3,tutor-end=5}{\}}\htmlData{tutor-start=5,tutor-end=6}{=}\htmlData{tutor-start=6,tutor-end=7}{x}\htmlData{tutor-start=7,tutor-end=8}{-}\htmlData{tutor-start=8,tutor-end=9}{[}\htmlData{tutor-start=9,tutor-end=10}{x}\htmlData{tutor-start=10,tutor-end=11}{]},而 [x]\htmlData{tutor-start=0,tutor-end=1}{[}\htmlData{tutor-start=1,tutor-end=2}{x}\htmlData{tutor-start=2,tutor-end=3}{]} 表示不超过 x\htmlData{tutor-start=0,tutor-end=1}{x} 的最大整数。求这种三角形周长的最小值。

题解状态:标准答案与规范题解待补充

题目标签:SECOND-GENERAL-PROBLEM-P二

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

18

二试/加试 · 加试题 · 平面几何

(本题 50 分) 由 n\htmlData{tutor-start=0,tutor-end=1}{n} 个点和这些点之间的 l\htmlData{tutor-start=0,tutor-end=1}{l} 条连线段组成一个空间图形,其中 n=q2+q+1\htmlData{tutor-start=0,tutor-end=1}{n}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=3}{q}^{\htmlData{tutor-start=5,tutor-end=6}{2}}\htmlData{tutor-start=7,tutor-end=8}{+}\htmlData{tutor-start=8,tutor-end=9}{q}\htmlData{tutor-start=9,tutor-end=10}{+}\htmlData{tutor-start=10,tutor-end=11}{1}l12q(q+1)2+1\htmlData{tutor-start=0,tutor-end=1}{l} \htmlData{tutor-start=2,tutor-end=12}{\geqslant }\frac{\htmlData{tutor-start=18,tutor-end=19}{1}}{\htmlData{tutor-start=21,tutor-end=22}{2}}\htmlData{tutor-start=23,tutor-end=24}{q}\htmlData{tutor-start=24,tutor-end=25}{(}\htmlData{tutor-start=25,tutor-end=26}{q}\htmlData{tutor-start=26,tutor-end=27}{+}\htmlData{tutor-start=27,tutor-end=28}{1}\htmlData{tutor-start=28,tutor-end=29}{)}^{\htmlData{tutor-start=31,tutor-end=32}{2}}\htmlData{tutor-start=33,tutor-end=34}{+}\htmlData{tutor-start=34,tutor-end=35}{1}q2\htmlData{tutor-start=0,tutor-end=1}{q} \htmlData{tutor-start=2,tutor-end=12}{\geqslant }\htmlData{tutor-start=12,tutor-end=13}{2}qN\htmlData{tutor-start=0,tutor-end=1}{q} \htmlData{tutor-start=2,tutor-end=6}{\in }\mathbb{\htmlData{tutor-start=14,tutor-end=15}{N}}。已知此图中任四点不共面,每点至少有一条连线段,存在一点至少有 q+2\htmlData{tutor-start=0,tutor-end=1}{q}\htmlData{tutor-start=1,tutor-end=2}{+}\htmlData{tutor-start=2,tutor-end=3}{2} 条连线段。证明:图中必存在一个空间四边形(即由四点 A\htmlData{tutor-start=0,tutor-end=1}{A}B\htmlData{tutor-start=0,tutor-end=1}{B}C\htmlData{tutor-start=0,tutor-end=1}{C}D\htmlData{tutor-start=0,tutor-end=1}{D} 和四条连线段 AB\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{B}BC\htmlData{tutor-start=0,tutor-end=1}{B}\htmlData{tutor-start=1,tutor-end=2}{C}CD\htmlData{tutor-start=0,tutor-end=1}{C}\htmlData{tutor-start=1,tutor-end=2}{D}DA\htmlData{tutor-start=0,tutor-end=1}{D}\htmlData{tutor-start=1,tutor-end=2}{A} 组成的图形)。

题解状态:标准答案与规范题解待补充

题目标签:SECOND-GENERAL-PROBLEM-P三

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。