返回特征解读

2020 年高考数学(上海卷)

exams_raw/普通高考/2020/2020上海.pdf · HS-MATH-1024-v2.1-solution-aware

210 个小问/题组
1

一、填空题 · 组合数学

若集合 A={1,2,4}\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=4}{\{}\htmlData{tutor-start=4,tutor-end=5}{1}\htmlData{tutor-start=5,tutor-end=6}{,} \htmlData{tutor-start=7,tutor-end=8}{2}\htmlData{tutor-start=8,tutor-end=9}{,} \htmlData{tutor-start=10,tutor-end=11}{4}\htmlData{tutor-start=11,tutor-end=13}{\}}, B={2,4,5}\htmlData{tutor-start=0,tutor-end=1}{B}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=4}{\{}\htmlData{tutor-start=4,tutor-end=5}{2}\htmlData{tutor-start=5,tutor-end=6}{,} \htmlData{tutor-start=7,tutor-end=8}{4}\htmlData{tutor-start=8,tutor-end=9}{,} \htmlData{tutor-start=10,tutor-end=11}{5}\htmlData{tutor-start=11,tutor-end=13}{\}}, 则 AB=\htmlData{tutor-start=0,tutor-end=1}{A} \htmlData{tutor-start=2,tutor-end=7}{\cap }\htmlData{tutor-start=7,tutor-end=8}{B}\htmlData{tutor-start=8,tutor-end=9}{=} ______.

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 1 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

2

一、填空题 · 数学竞赛/待细分

计算: limnn+13n1=\lim_{\htmlData{tutor-start=6,tutor-end=7}{n} \htmlData{tutor-start=8,tutor-end=12}{\to }\htmlData{tutor-start=12,tutor-end=18}{\infty}} \frac{\htmlData{tutor-start=26,tutor-end=27}{n}\htmlData{tutor-start=27,tutor-end=28}{+}\htmlData{tutor-start=28,tutor-end=29}{1}}{\htmlData{tutor-start=31,tutor-end=32}{3}\htmlData{tutor-start=32,tutor-end=33}{n}\htmlData{tutor-start=33,tutor-end=34}{-}\htmlData{tutor-start=34,tutor-end=35}{1}} \htmlData{tutor-start=37,tutor-end=38}{=} ______.

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 2 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

3

一、填空题 · 数学竞赛/待细分

若复数 z=12i\htmlData{tutor-start=0,tutor-end=1}{z}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=3}{1}\htmlData{tutor-start=3,tutor-end=4}{-}\htmlData{tutor-start=4,tutor-end=5}{2}\mathrm{\htmlData{tutor-start=13,tutor-end=14}{i}} (其中 i\mathrm{\htmlData{tutor-start=8,tutor-end=9}{i}} 为虚数单位), 则 z=\htmlData{tutor-start=0,tutor-end=1}{|}\htmlData{tutor-start=1,tutor-end=2}{z}\htmlData{tutor-start=2,tutor-end=3}{|}\htmlData{tutor-start=3,tutor-end=4}{=} ______.

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 3 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

4

一、填空题 · 代数

函数 f(x)=x3\htmlData{tutor-start=0,tutor-end=1}{f}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{x}\htmlData{tutor-start=3,tutor-end=4}{)}\htmlData{tutor-start=4,tutor-end=5}{=}\htmlData{tutor-start=5,tutor-end=6}{x}^{\htmlData{tutor-start=8,tutor-end=9}{3}} 的反函数为______.

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 4 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

5

一、填空题 · 数学竞赛/待细分

若实数 x,y\htmlData{tutor-start=0,tutor-end=1}{x}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{y} 满足 {x+y20,x+2y30,y0,\begin{cases} \htmlData{tutor-start=14,tutor-end=15}{x}\htmlData{tutor-start=15,tutor-end=16}{+}\htmlData{tutor-start=16,tutor-end=17}{y}\htmlData{tutor-start=17,tutor-end=18}{-}\htmlData{tutor-start=18,tutor-end=19}{2} \htmlData{tutor-start=20,tutor-end=30}{\geqslant }\htmlData{tutor-start=30,tutor-end=31}{0}\htmlData{tutor-start=31,tutor-end=32}{,} \\ \htmlData{tutor-start=36,tutor-end=37}{x}\htmlData{tutor-start=37,tutor-end=38}{+}\htmlData{tutor-start=38,tutor-end=39}{2}\htmlData{tutor-start=39,tutor-end=40}{y}\htmlData{tutor-start=40,tutor-end=41}{-}\htmlData{tutor-start=41,tutor-end=42}{3} \htmlData{tutor-start=43,tutor-end=53}{\leqslant }\htmlData{tutor-start=53,tutor-end=54}{0}\htmlData{tutor-start=54,tutor-end=55}{,} \\ \htmlData{tutor-start=59,tutor-end=60}{y} \htmlData{tutor-start=61,tutor-end=71}{\geqslant }\htmlData{tutor-start=71,tutor-end=72}{0}\htmlData{tutor-start=72,tutor-end=73}{,} \end{cases}z=y2x\htmlData{tutor-start=0,tutor-end=1}{z}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=3}{y}\htmlData{tutor-start=3,tutor-end=4}{-}\htmlData{tutor-start=4,tutor-end=5}{2}\htmlData{tutor-start=5,tutor-end=6}{x} 的最大值为______.

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 5 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

6

一、填空题 · 数学竞赛/待细分

a,b,c,dR\htmlData{tutor-start=0,tutor-end=1}{a}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{b}\htmlData{tutor-start=4,tutor-end=5}{,} \htmlData{tutor-start=6,tutor-end=7}{c}\htmlData{tutor-start=7,tutor-end=8}{,} \htmlData{tutor-start=9,tutor-end=10}{d} \htmlData{tutor-start=11,tutor-end=15}{\in }\mathbf{\htmlData{tutor-start=23,tutor-end=24}{R}}, 若行列式 1ab2cd300=6\begin{vmatrix} \htmlData{tutor-start=16,tutor-end=17}{1} & \htmlData{tutor-start=20,tutor-end=21}{a} & \htmlData{tutor-start=24,tutor-end=25}{b} \\ \htmlData{tutor-start=29,tutor-end=30}{2} & \htmlData{tutor-start=33,tutor-end=34}{c} & \htmlData{tutor-start=37,tutor-end=38}{d} \\ \htmlData{tutor-start=42,tutor-end=43}{3} & \htmlData{tutor-start=46,tutor-end=47}{0} & \htmlData{tutor-start=50,tutor-end=51}{0} \end{vmatrix} \htmlData{tutor-start=66,tutor-end=67}{=} \htmlData{tutor-start=68,tutor-end=69}{6}, 则行列式 abcd=\begin{vmatrix} \htmlData{tutor-start=16,tutor-end=17}{a} & \htmlData{tutor-start=20,tutor-end=21}{b} \\ \htmlData{tutor-start=25,tutor-end=26}{c} & \htmlData{tutor-start=29,tutor-end=30}{d} \end{vmatrix} \htmlData{tutor-start=45,tutor-end=46}{=} ______.

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 6 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

7

一、填空题 · 数学竞赛/待细分

a,bR\htmlData{tutor-start=0,tutor-end=1}{a}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{b} \htmlData{tutor-start=5,tutor-end=9}{\in }\mathbf{\htmlData{tutor-start=17,tutor-end=18}{R}}, 若 1,2,a,b\htmlData{tutor-start=0,tutor-end=1}{1}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{2}\htmlData{tutor-start=4,tutor-end=5}{,} \htmlData{tutor-start=6,tutor-end=7}{a}\htmlData{tutor-start=7,tutor-end=8}{,} \htmlData{tutor-start=9,tutor-end=10}{b} 这四个数的中位数为 3\htmlData{tutor-start=0,tutor-end=1}{3}, 平均数为 4\htmlData{tutor-start=0,tutor-end=1}{4}, 则 ab=\htmlData{tutor-start=0,tutor-end=1}{a}\htmlData{tutor-start=1,tutor-end=2}{b}\htmlData{tutor-start=2,tutor-end=3}{=} ______.

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 7 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

8

一、填空题 · 代数

已知公差不为 0\htmlData{tutor-start=0,tutor-end=1}{0} 的等差数列 {an}\htmlData{tutor-start=0,tutor-end=2}{\{}\htmlData{tutor-start=2,tutor-end=3}{a}_{\htmlData{tutor-start=5,tutor-end=6}{n}}\htmlData{tutor-start=7,tutor-end=9}{\}}, 其前 n\htmlData{tutor-start=0,tutor-end=1}{n} 项和为 Sn\htmlData{tutor-start=0,tutor-end=1}{S}_{\htmlData{tutor-start=3,tutor-end=4}{n}}, 若 a1+a10=a9\htmlData{tutor-start=0,tutor-end=1}{a}_{\htmlData{tutor-start=3,tutor-end=4}{1}}\htmlData{tutor-start=5,tutor-end=6}{+}\htmlData{tutor-start=6,tutor-end=7}{a}_{\htmlData{tutor-start=9,tutor-end=10}{1}\htmlData{tutor-start=10,tutor-end=11}{0}}\htmlData{tutor-start=12,tutor-end=13}{=}\htmlData{tutor-start=13,tutor-end=14}{a}_{\htmlData{tutor-start=16,tutor-end=17}{9}}, 则 S9a10=\frac{\htmlData{tutor-start=6,tutor-end=7}{S}_{\htmlData{tutor-start=9,tutor-end=10}{9}}}{\htmlData{tutor-start=13,tutor-end=14}{a}_{\htmlData{tutor-start=16,tutor-end=17}{1}\htmlData{tutor-start=17,tutor-end=18}{0}}}\htmlData{tutor-start=20,tutor-end=21}{=} ______.

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 8 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

9

一、填空题 · 数学竞赛/待细分

6\htmlData{tutor-start=0,tutor-end=1}{6} 人中选出 4\htmlData{tutor-start=0,tutor-end=1}{4} 人去值班, 每人值班一天, 若第一天安排 1\htmlData{tutor-start=0,tutor-end=1}{1} 人, 第二天安排 1\htmlData{tutor-start=0,tutor-end=1}{1} 人, 第三天安排 2\htmlData{tutor-start=0,tutor-end=1}{2} 人, 则不同安排方法的种数为______. (结果用数值表示)

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 9 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

10

一、填空题 · 平面几何

已知椭圆 Γ:x24+y23=1\htmlData{tutor-start=0,tutor-end=6}{\Gamma}\htmlData{tutor-start=6,tutor-end=7}{:} \frac{\htmlData{tutor-start=14,tutor-end=15}{x}^{\htmlData{tutor-start=17,tutor-end=18}{2}}}{\htmlData{tutor-start=21,tutor-end=22}{4}} \htmlData{tutor-start=24,tutor-end=25}{+} \frac{\htmlData{tutor-start=32,tutor-end=33}{y}^{\htmlData{tutor-start=35,tutor-end=36}{2}}}{\htmlData{tutor-start=39,tutor-end=40}{3}} \htmlData{tutor-start=42,tutor-end=43}{=} \htmlData{tutor-start=44,tutor-end=45}{1} 的右焦点为 F\htmlData{tutor-start=0,tutor-end=1}{F}, 点 P\htmlData{tutor-start=0,tutor-end=1}{P} 位于第二象限且在 Γ\htmlData{tutor-start=0,tutor-end=6}{\Gamma} 上, 联结 PF\htmlData{tutor-start=0,tutor-end=1}{P}\htmlData{tutor-start=1,tutor-end=2}{F} 并延长, 交 Γ\htmlData{tutor-start=0,tutor-end=6}{\Gamma} 于点 Q(xQ,yQ)\htmlData{tutor-start=0,tutor-end=1}{Q}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{x}_{\htmlData{tutor-start=5,tutor-end=6}{Q}}\htmlData{tutor-start=7,tutor-end=8}{,} \htmlData{tutor-start=9,tutor-end=10}{y}_{\htmlData{tutor-start=12,tutor-end=13}{Q}}\htmlData{tutor-start=14,tutor-end=15}{)}, 点 Q(xQ,yQ)\htmlData{tutor-start=0,tutor-end=1}{Q}'\htmlData{tutor-start=2,tutor-end=3}{(}\htmlData{tutor-start=3,tutor-end=4}{x}_{\htmlData{tutor-start=6,tutor-end=7}{Q}'}\htmlData{tutor-start=9,tutor-end=10}{,} \htmlData{tutor-start=11,tutor-end=12}{y}_{\htmlData{tutor-start=14,tutor-end=15}{Q}'}\htmlData{tutor-start=17,tutor-end=18}{)} 也在 Γ\htmlData{tutor-start=0,tutor-end=6}{\Gamma} 上, 且 yQ+yQ=0\htmlData{tutor-start=0,tutor-end=1}{y}_{\htmlData{tutor-start=3,tutor-end=4}{Q}} \htmlData{tutor-start=6,tutor-end=7}{+} \htmlData{tutor-start=8,tutor-end=9}{y}_{\htmlData{tutor-start=11,tutor-end=12}{Q}'} \htmlData{tutor-start=15,tutor-end=16}{=} \htmlData{tutor-start=17,tutor-end=18}{0}. 若 FQFP\htmlData{tutor-start=0,tutor-end=1}{F}\htmlData{tutor-start=1,tutor-end=2}{Q}' \htmlData{tutor-start=4,tutor-end=10}{\perp }\htmlData{tutor-start=10,tutor-end=11}{F}\htmlData{tutor-start=11,tutor-end=12}{P}, 则直线 PQ\htmlData{tutor-start=0,tutor-end=1}{P}\htmlData{tutor-start=1,tutor-end=2}{Q} 的方程为______.

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 10 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

11

一、填空题 · 代数

aR\htmlData{tutor-start=0,tutor-end=1}{a} \htmlData{tutor-start=2,tutor-end=6}{\in }\mathbf{\htmlData{tutor-start=14,tutor-end=15}{R}}, 若存在定义域为 R\mathbf{\htmlData{tutor-start=8,tutor-end=9}{R}} 的函数 f(x)\htmlData{tutor-start=0,tutor-end=1}{f}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{x}\htmlData{tutor-start=3,tutor-end=4}{)} 既满足“对任意 x0R\htmlData{tutor-start=0,tutor-end=1}{x}_{\htmlData{tutor-start=3,tutor-end=4}{0}} \htmlData{tutor-start=6,tutor-end=10}{\in }\mathbf{\htmlData{tutor-start=18,tutor-end=19}{R}}, f(x0)\htmlData{tutor-start=0,tutor-end=1}{f}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{x}_{\htmlData{tutor-start=5,tutor-end=6}{0}}\htmlData{tutor-start=7,tutor-end=8}{)} 的值为 x02\htmlData{tutor-start=0,tutor-end=1}{x}_{\htmlData{tutor-start=3,tutor-end=4}{0}}^{\htmlData{tutor-start=7,tutor-end=8}{2}}x0\htmlData{tutor-start=0,tutor-end=1}{x}_{\htmlData{tutor-start=3,tutor-end=4}{0}}”又满足“关于 x\htmlData{tutor-start=0,tutor-end=1}{x} 的方程 f(x)=a\htmlData{tutor-start=0,tutor-end=1}{f}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{x}\htmlData{tutor-start=3,tutor-end=4}{)}\htmlData{tutor-start=4,tutor-end=5}{=}\htmlData{tutor-start=5,tutor-end=6}{a} 无实数解”, 则 a\htmlData{tutor-start=0,tutor-end=1}{a} 取值范围是______.

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 11 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

12

一、填空题 · 数学竞赛/待细分

已知 a1,a2,b1,b2,,bk\boldsymbol{a}_{1}, \boldsymbol{a}_{2}, \boldsymbol{b}_{1}, \boldsymbol{b}_{2}, \cdots, \boldsymbol{b}_{k} 是平面内两两互不相等的向量, 若 a1a2=1\htmlData{tutor-start=0,tutor-end=1}{|}\boldsymbol{\htmlData{tutor-start=13,tutor-end=14}{a}}_{\htmlData{tutor-start=17,tutor-end=18}{1}} \htmlData{tutor-start=20,tutor-end=21}{-} \boldsymbol{\htmlData{tutor-start=34,tutor-end=35}{a}}_{\htmlData{tutor-start=38,tutor-end=39}{2}}\htmlData{tutor-start=40,tutor-end=41}{|} \htmlData{tutor-start=42,tutor-end=43}{=} \htmlData{tutor-start=44,tutor-end=45}{1}, 且 aibj{1,2}\htmlData{tutor-start=0,tutor-end=1}{|}\boldsymbol{\htmlData{tutor-start=13,tutor-end=14}{a}}_{\htmlData{tutor-start=17,tutor-end=18}{i}} \htmlData{tutor-start=20,tutor-end=21}{-} \boldsymbol{\htmlData{tutor-start=34,tutor-end=35}{b}}_{\htmlData{tutor-start=38,tutor-end=39}{j}}\htmlData{tutor-start=40,tutor-end=41}{|} \htmlData{tutor-start=42,tutor-end=46}{\in }\htmlData{tutor-start=46,tutor-end=48}{\{}\htmlData{tutor-start=48,tutor-end=49}{1}\htmlData{tutor-start=49,tutor-end=50}{,} \htmlData{tutor-start=51,tutor-end=52}{2}\htmlData{tutor-start=52,tutor-end=54}{\}} (其中 i=1,2,j=1,2,,k\htmlData{tutor-start=0,tutor-end=1}{i}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=3}{1}\htmlData{tutor-start=3,tutor-end=4}{,} \htmlData{tutor-start=5,tutor-end=6}{2}\htmlData{tutor-start=6,tutor-end=7}{,} \htmlData{tutor-start=8,tutor-end=9}{j}\htmlData{tutor-start=9,tutor-end=10}{=}\htmlData{tutor-start=10,tutor-end=11}{1}\htmlData{tutor-start=11,tutor-end=12}{,} \htmlData{tutor-start=13,tutor-end=14}{2}\htmlData{tutor-start=14,tutor-end=15}{,} \cdots\htmlData{tutor-start=22,tutor-end=23}{,} \htmlData{tutor-start=24,tutor-end=25}{k}), 则 k\htmlData{tutor-start=0,tutor-end=1}{k} 最大值为______.

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 12 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

13

二、选择题 · 代数

a,bR\htmlData{tutor-start=0,tutor-end=1}{a}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{b} \htmlData{tutor-start=5,tutor-end=9}{\in }\mathbf{\htmlData{tutor-start=17,tutor-end=18}{R}}, 则下列不等式中, 恒成立的是 ( ) (A) a2+b22ab\htmlData{tutor-start=0,tutor-end=1}{a}^{\htmlData{tutor-start=3,tutor-end=4}{2}}\htmlData{tutor-start=5,tutor-end=6}{+}\htmlData{tutor-start=6,tutor-end=7}{b}^{\htmlData{tutor-start=9,tutor-end=10}{2}} \htmlData{tutor-start=12,tutor-end=22}{\leqslant }\htmlData{tutor-start=22,tutor-end=23}{2}\htmlData{tutor-start=23,tutor-end=24}{a}\htmlData{tutor-start=24,tutor-end=25}{b} (B) a2+b22ab\htmlData{tutor-start=0,tutor-end=1}{a}^{\htmlData{tutor-start=3,tutor-end=4}{2}}\htmlData{tutor-start=5,tutor-end=6}{+}\htmlData{tutor-start=6,tutor-end=7}{b}^{\htmlData{tutor-start=9,tutor-end=10}{2}} \htmlData{tutor-start=12,tutor-end=22}{\geqslant }\htmlData{tutor-start=22,tutor-end=23}{-}\htmlData{tutor-start=23,tutor-end=24}{2}\htmlData{tutor-start=24,tutor-end=25}{a}\htmlData{tutor-start=25,tutor-end=26}{b} (C) a+b2ab\htmlData{tutor-start=0,tutor-end=1}{a}\htmlData{tutor-start=1,tutor-end=2}{+}\htmlData{tutor-start=2,tutor-end=3}{b} \htmlData{tutor-start=4,tutor-end=14}{\geqslant }\htmlData{tutor-start=14,tutor-end=15}{2}\sqrt{\htmlData{tutor-start=21,tutor-end=22}{|}\htmlData{tutor-start=22,tutor-end=23}{a}\htmlData{tutor-start=23,tutor-end=24}{b}\htmlData{tutor-start=24,tutor-end=25}{|}} (D) a+b2ab\htmlData{tutor-start=0,tutor-end=1}{a}\htmlData{tutor-start=1,tutor-end=2}{+}\htmlData{tutor-start=2,tutor-end=3}{b} \htmlData{tutor-start=4,tutor-end=14}{\geqslant }\htmlData{tutor-start=14,tutor-end=15}{-}\htmlData{tutor-start=15,tutor-end=16}{2}\sqrt{\htmlData{tutor-start=22,tutor-end=23}{|}\htmlData{tutor-start=23,tutor-end=24}{a}\htmlData{tutor-start=24,tutor-end=25}{b}\htmlData{tutor-start=25,tutor-end=26}{|}}

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 13 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

14

二、选择题 · 平面几何

直线 3x+4y+1=0\htmlData{tutor-start=0,tutor-end=1}{3}\htmlData{tutor-start=1,tutor-end=2}{x}\htmlData{tutor-start=2,tutor-end=3}{+}\htmlData{tutor-start=3,tutor-end=4}{4}\htmlData{tutor-start=4,tutor-end=5}{y}\htmlData{tutor-start=5,tutor-end=6}{+}\htmlData{tutor-start=6,tutor-end=7}{1}\htmlData{tutor-start=7,tutor-end=8}{=}\htmlData{tutor-start=8,tutor-end=9}{0} 的一个参数方程可以为 ( ) (A) {x=1+3t,y=1+4t,\begin{cases} \htmlData{tutor-start=14,tutor-end=15}{x}\htmlData{tutor-start=15,tutor-end=16}{=}\htmlData{tutor-start=16,tutor-end=17}{1}\htmlData{tutor-start=17,tutor-end=18}{+}\htmlData{tutor-start=18,tutor-end=19}{3}\htmlData{tutor-start=19,tutor-end=20}{t}\htmlData{tutor-start=20,tutor-end=21}{,} \\ \htmlData{tutor-start=25,tutor-end=26}{y}\htmlData{tutor-start=26,tutor-end=27}{=}\htmlData{tutor-start=27,tutor-end=28}{-}\htmlData{tutor-start=28,tutor-end=29}{1}\htmlData{tutor-start=29,tutor-end=30}{+}\htmlData{tutor-start=30,tutor-end=31}{4}\htmlData{tutor-start=31,tutor-end=32}{t}\htmlData{tutor-start=32,tutor-end=33}{,} \end{cases} (t\htmlData{tutor-start=0,tutor-end=1}{t} 为参数) (B) {x=13t,y=1+4t,\begin{cases} \htmlData{tutor-start=14,tutor-end=15}{x}\htmlData{tutor-start=15,tutor-end=16}{=}\htmlData{tutor-start=16,tutor-end=17}{1}\htmlData{tutor-start=17,tutor-end=18}{-}\htmlData{tutor-start=18,tutor-end=19}{3}\htmlData{tutor-start=19,tutor-end=20}{t}\htmlData{tutor-start=20,tutor-end=21}{,} \\ \htmlData{tutor-start=25,tutor-end=26}{y}\htmlData{tutor-start=26,tutor-end=27}{=}\htmlData{tutor-start=27,tutor-end=28}{-}\htmlData{tutor-start=28,tutor-end=29}{1}\htmlData{tutor-start=29,tutor-end=30}{+}\htmlData{tutor-start=30,tutor-end=31}{4}\htmlData{tutor-start=31,tutor-end=32}{t}\htmlData{tutor-start=32,tutor-end=33}{,} \end{cases} (t\htmlData{tutor-start=0,tutor-end=1}{t} 为参数) (C) {x=14t,y=13t,\begin{cases} \htmlData{tutor-start=14,tutor-end=15}{x}\htmlData{tutor-start=15,tutor-end=16}{=}\htmlData{tutor-start=16,tutor-end=17}{1}\htmlData{tutor-start=17,tutor-end=18}{-}\htmlData{tutor-start=18,tutor-end=19}{4}\htmlData{tutor-start=19,tutor-end=20}{t}\htmlData{tutor-start=20,tutor-end=21}{,} \\ \htmlData{tutor-start=25,tutor-end=26}{y}\htmlData{tutor-start=26,tutor-end=27}{=}\htmlData{tutor-start=27,tutor-end=28}{-}\htmlData{tutor-start=28,tutor-end=29}{1}\htmlData{tutor-start=29,tutor-end=30}{-}\htmlData{tutor-start=30,tutor-end=31}{3}\htmlData{tutor-start=31,tutor-end=32}{t}\htmlData{tutor-start=32,tutor-end=33}{,} \end{cases} (t\htmlData{tutor-start=0,tutor-end=1}{t} 为参数) (D) {x=1+4t,y=13t,\begin{cases} \htmlData{tutor-start=14,tutor-end=15}{x}\htmlData{tutor-start=15,tutor-end=16}{=}\htmlData{tutor-start=16,tutor-end=17}{1}\htmlData{tutor-start=17,tutor-end=18}{+}\htmlData{tutor-start=18,tutor-end=19}{4}\htmlData{tutor-start=19,tutor-end=20}{t}\htmlData{tutor-start=20,tutor-end=21}{,} \\ \htmlData{tutor-start=25,tutor-end=26}{y}\htmlData{tutor-start=26,tutor-end=27}{=}\htmlData{tutor-start=27,tutor-end=28}{-}\htmlData{tutor-start=28,tutor-end=29}{1}\htmlData{tutor-start=29,tutor-end=30}{-}\htmlData{tutor-start=30,tutor-end=31}{3}\htmlData{tutor-start=31,tutor-end=32}{t}\htmlData{tutor-start=32,tutor-end=33}{,} \end{cases} (t\htmlData{tutor-start=0,tutor-end=1}{t} 为参数)

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 14 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

15

二、选择题 · 平面几何

在如图所示的棱长为 10\htmlData{tutor-start=0,tutor-end=1}{1}\htmlData{tutor-start=1,tutor-end=2}{0} 的正方体 ABCDA1B1C1D1\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{B}\htmlData{tutor-start=2,tutor-end=3}{C}\htmlData{tutor-start=3,tutor-end=4}{D}\htmlData{tutor-start=4,tutor-end=5}{-}\htmlData{tutor-start=5,tutor-end=6}{A}_{\htmlData{tutor-start=8,tutor-end=9}{1}}\htmlData{tutor-start=10,tutor-end=11}{B}_{\htmlData{tutor-start=13,tutor-end=14}{1}}\htmlData{tutor-start=15,tutor-end=16}{C}_{\htmlData{tutor-start=18,tutor-end=19}{1}}\htmlData{tutor-start=20,tutor-end=21}{D}_{\htmlData{tutor-start=23,tutor-end=24}{1}} 中, 一条平行于 A1C\htmlData{tutor-start=0,tutor-end=1}{A}_{\htmlData{tutor-start=3,tutor-end=4}{1}}\htmlData{tutor-start=5,tutor-end=6}{C} 的直线与正方体的表面交于 P,Q\htmlData{tutor-start=0,tutor-end=1}{P}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{Q} 两点, 其中 P\htmlData{tutor-start=0,tutor-end=1}{P} 在侧面 ADD1A1\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{D}\htmlData{tutor-start=2,tutor-end=3}{D}_{\htmlData{tutor-start=5,tutor-end=6}{1}}\htmlData{tutor-start=7,tutor-end=8}{A}_{\htmlData{tutor-start=10,tutor-end=11}{1}} 上, 且到 A1D1\htmlData{tutor-start=0,tutor-end=1}{A}_{\htmlData{tutor-start=3,tutor-end=4}{1}}\htmlData{tutor-start=5,tutor-end=6}{D}_{\htmlData{tutor-start=8,tutor-end=9}{1}} 的距离为 3\htmlData{tutor-start=0,tutor-end=1}{3}, 到 AA1\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{A}_{\htmlData{tutor-start=4,tutor-end=5}{1}} 的距离为 2\htmlData{tutor-start=0,tutor-end=1}{2}, 则点 Q\htmlData{tutor-start=0,tutor-end=1}{Q} 所在的面是 ( ) (A) ABCD\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{B}\htmlData{tutor-start=2,tutor-end=3}{C}\htmlData{tutor-start=3,tutor-end=4}{D} (B) ABB1A1\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{B}\htmlData{tutor-start=2,tutor-end=3}{B}_{\htmlData{tutor-start=5,tutor-end=6}{1}}\htmlData{tutor-start=7,tutor-end=8}{A}_{\htmlData{tutor-start=10,tutor-end=11}{1}} (C) BCC1B1\htmlData{tutor-start=0,tutor-end=1}{B}\htmlData{tutor-start=1,tutor-end=2}{C}\htmlData{tutor-start=2,tutor-end=3}{C}_{\htmlData{tutor-start=5,tutor-end=6}{1}}\htmlData{tutor-start=7,tutor-end=8}{B}_{\htmlData{tutor-start=10,tutor-end=11}{1}} (D) CDD1C1\htmlData{tutor-start=0,tutor-end=1}{C}\htmlData{tutor-start=1,tutor-end=2}{D}\htmlData{tutor-start=2,tutor-end=3}{D}_{\htmlData{tutor-start=5,tutor-end=6}{1}}\htmlData{tutor-start=7,tutor-end=8}{C}_{\htmlData{tutor-start=10,tutor-end=11}{1}}

原卷图示 1
原卷图示 1原卷第 1 页 · qwen3.7-plus_layout_detection · 需复核

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 15 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

16

二、选择题 · 代数

对于定义在 R\mathbf{\htmlData{tutor-start=8,tutor-end=9}{R}} 上的函数 y=f(x)\htmlData{tutor-start=0,tutor-end=1}{y}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=3}{f}\htmlData{tutor-start=3,tutor-end=4}{(}\htmlData{tutor-start=4,tutor-end=5}{x}\htmlData{tutor-start=5,tutor-end=6}{)}, 考察以下性质: p\htmlData{tutor-start=0,tutor-end=1}{p}: 存在非零实数 a\htmlData{tutor-start=0,tutor-end=1}{a}, 使得 f(x+a)<f(x)+f(a)\htmlData{tutor-start=0,tutor-end=1}{f}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{x}\htmlData{tutor-start=3,tutor-end=4}{+}\htmlData{tutor-start=4,tutor-end=5}{a}\htmlData{tutor-start=5,tutor-end=6}{)} \htmlData{tutor-start=7,tutor-end=8}{<} \htmlData{tutor-start=9,tutor-end=10}{f}\htmlData{tutor-start=10,tutor-end=11}{(}\htmlData{tutor-start=11,tutor-end=12}{x}\htmlData{tutor-start=12,tutor-end=13}{)}\htmlData{tutor-start=13,tutor-end=14}{+}\htmlData{tutor-start=14,tutor-end=15}{f}\htmlData{tutor-start=15,tutor-end=16}{(}\htmlData{tutor-start=16,tutor-end=17}{a}\htmlData{tutor-start=17,tutor-end=18}{)} 对任意的 xR\htmlData{tutor-start=0,tutor-end=1}{x} \htmlData{tutor-start=2,tutor-end=6}{\in }\mathbf{\htmlData{tutor-start=14,tutor-end=15}{R}} 恒成立; q1\htmlData{tutor-start=0,tutor-end=1}{q}_{\htmlData{tutor-start=3,tutor-end=4}{1}}: y=f(x)\htmlData{tutor-start=0,tutor-end=1}{y}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=3}{f}\htmlData{tutor-start=3,tutor-end=4}{(}\htmlData{tutor-start=4,tutor-end=5}{x}\htmlData{tutor-start=5,tutor-end=6}{)} 单调递减, 且 f(x)\htmlData{tutor-start=0,tutor-end=1}{f}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{x}\htmlData{tutor-start=3,tutor-end=4}{)} 恒大于 0\htmlData{tutor-start=0,tutor-end=1}{0}; q2\htmlData{tutor-start=0,tutor-end=1}{q}_{\htmlData{tutor-start=3,tutor-end=4}{2}}: y=f(x)\htmlData{tutor-start=0,tutor-end=1}{y}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=3}{f}\htmlData{tutor-start=3,tutor-end=4}{(}\htmlData{tutor-start=4,tutor-end=5}{x}\htmlData{tutor-start=5,tutor-end=6}{)} 单调递增, 且存在 x0<0\htmlData{tutor-start=0,tutor-end=1}{x}_{\htmlData{tutor-start=3,tutor-end=4}{0}} \htmlData{tutor-start=6,tutor-end=7}{<} \htmlData{tutor-start=8,tutor-end=9}{0}, 使得 f(x0)=0\htmlData{tutor-start=0,tutor-end=1}{f}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{x}_{\htmlData{tutor-start=5,tutor-end=6}{0}}\htmlData{tutor-start=7,tutor-end=8}{)}\htmlData{tutor-start=8,tutor-end=9}{=}\htmlData{tutor-start=9,tutor-end=10}{0}. 关于上述性质, 以下判断正确的是 ( ) (A) q1,q2\htmlData{tutor-start=0,tutor-end=1}{q}_{\htmlData{tutor-start=3,tutor-end=4}{1}}\htmlData{tutor-start=5,tutor-end=6}{,} \htmlData{tutor-start=7,tutor-end=8}{q}_{\htmlData{tutor-start=10,tutor-end=11}{2}} 都是 p\htmlData{tutor-start=0,tutor-end=1}{p} 的充分条件 (B) q1,q2\htmlData{tutor-start=0,tutor-end=1}{q}_{\htmlData{tutor-start=3,tutor-end=4}{1}}\htmlData{tutor-start=5,tutor-end=6}{,} \htmlData{tutor-start=7,tutor-end=8}{q}_{\htmlData{tutor-start=10,tutor-end=11}{2}} 中仅 q1\htmlData{tutor-start=0,tutor-end=1}{q}_{\htmlData{tutor-start=3,tutor-end=4}{1}}p\htmlData{tutor-start=0,tutor-end=1}{p} 的充分条件 (C) q1,q2\htmlData{tutor-start=0,tutor-end=1}{q}_{\htmlData{tutor-start=3,tutor-end=4}{1}}\htmlData{tutor-start=5,tutor-end=6}{,} \htmlData{tutor-start=7,tutor-end=8}{q}_{\htmlData{tutor-start=10,tutor-end=11}{2}} 中仅 q2\htmlData{tutor-start=0,tutor-end=1}{q}_{\htmlData{tutor-start=3,tutor-end=4}{2}}p\htmlData{tutor-start=0,tutor-end=1}{p} 的充分条件 (D) q1,q2\htmlData{tutor-start=0,tutor-end=1}{q}_{\htmlData{tutor-start=3,tutor-end=4}{1}}\htmlData{tutor-start=5,tutor-end=6}{,} \htmlData{tutor-start=7,tutor-end=8}{q}_{\htmlData{tutor-start=10,tutor-end=11}{2}} 都不是 p\htmlData{tutor-start=0,tutor-end=1}{p} 的充分条件

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 16 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

17

三、解答题 · 平面几何

如图所示, 边长为 1\htmlData{tutor-start=0,tutor-end=1}{1} 的正方形 ABCD\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{B}\htmlData{tutor-start=2,tutor-end=3}{C}\htmlData{tutor-start=3,tutor-end=4}{D}BC\htmlData{tutor-start=0,tutor-end=1}{B}\htmlData{tutor-start=1,tutor-end=2}{C} 边旋转后形成一个圆柱. (1) 求该圆柱表面积 S\htmlData{tutor-start=0,tutor-end=1}{S}; (2) 正方形 ABCD\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{B}\htmlData{tutor-start=2,tutor-end=3}{C}\htmlData{tutor-start=3,tutor-end=4}{D}BC\htmlData{tutor-start=0,tutor-end=1}{B}\htmlData{tutor-start=1,tutor-end=2}{C} 逆时针旋转 π2\frac{\htmlData{tutor-start=6,tutor-end=9}{\pi}}{\htmlData{tutor-start=11,tutor-end=12}{2}}A1BCD1\htmlData{tutor-start=0,tutor-end=1}{A}_{\htmlData{tutor-start=3,tutor-end=4}{1}}\htmlData{tutor-start=5,tutor-end=6}{B}\htmlData{tutor-start=6,tutor-end=7}{C}\htmlData{tutor-start=7,tutor-end=8}{D}_{\htmlData{tutor-start=10,tutor-end=11}{1}}, 求 AD1\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{D}_{\htmlData{tutor-start=4,tutor-end=5}{1}} 与平面 ABCD\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{B}\htmlData{tutor-start=2,tutor-end=3}{C}\htmlData{tutor-start=3,tutor-end=4}{D} 所成角的大小. (结果用反三角函数值表示)

原卷图示 1
原卷图示 1原卷第 1 页 · qwen3.7-plus_layout_detection · 需复核

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 17 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

18

三、解答题 · 代数

已知函数 f(x)=sinωx\htmlData{tutor-start=0,tutor-end=1}{f}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{x}\htmlData{tutor-start=3,tutor-end=4}{)}\htmlData{tutor-start=4,tutor-end=5}{=}\sin \htmlData{tutor-start=10,tutor-end=17}{\omega }\htmlData{tutor-start=17,tutor-end=18}{x} (ω>0\htmlData{tutor-start=0,tutor-end=7}{\omega }\htmlData{tutor-start=7,tutor-end=8}{>} \htmlData{tutor-start=9,tutor-end=10}{0}). (1) 若函数 y=f(x)\htmlData{tutor-start=0,tutor-end=1}{y}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=3}{f}\htmlData{tutor-start=3,tutor-end=4}{(}\htmlData{tutor-start=4,tutor-end=5}{x}\htmlData{tutor-start=5,tutor-end=6}{)} 的周期为 4π\htmlData{tutor-start=0,tutor-end=1}{4}\htmlData{tutor-start=1,tutor-end=4}{\pi}, 求 ω\htmlData{tutor-start=0,tutor-end=6}{\omega} 及此时 f(x)=12\htmlData{tutor-start=0,tutor-end=1}{f}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{x}\htmlData{tutor-start=3,tutor-end=4}{)}\htmlData{tutor-start=4,tutor-end=5}{=}\frac{\htmlData{tutor-start=11,tutor-end=12}{1}}{\htmlData{tutor-start=14,tutor-end=15}{2}} 的解集; (2) 若 ω=1\htmlData{tutor-start=0,tutor-end=6}{\omega}\htmlData{tutor-start=6,tutor-end=7}{=}\htmlData{tutor-start=7,tutor-end=8}{1}, 设 g(x)=f2(x)+3f(x)f(π2x)\htmlData{tutor-start=0,tutor-end=1}{g}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{x}\htmlData{tutor-start=3,tutor-end=4}{)}\htmlData{tutor-start=4,tutor-end=5}{=}\htmlData{tutor-start=5,tutor-end=6}{f}^{\htmlData{tutor-start=8,tutor-end=9}{2}}\htmlData{tutor-start=10,tutor-end=11}{(}\htmlData{tutor-start=11,tutor-end=12}{x}\htmlData{tutor-start=12,tutor-end=13}{)}\htmlData{tutor-start=13,tutor-end=14}{+}\sqrt{\htmlData{tutor-start=20,tutor-end=21}{3}}\htmlData{tutor-start=22,tutor-end=23}{f}\htmlData{tutor-start=23,tutor-end=24}{(}\htmlData{tutor-start=24,tutor-end=25}{-}\htmlData{tutor-start=25,tutor-end=26}{x}\htmlData{tutor-start=26,tutor-end=27}{)} \htmlData{tutor-start=28,tutor-end=34}{\cdot }\htmlData{tutor-start=34,tutor-end=35}{f}\left(\frac{\htmlData{tutor-start=47,tutor-end=50}{\pi}}{\htmlData{tutor-start=52,tutor-end=53}{2}}\htmlData{tutor-start=54,tutor-end=55}{-}\htmlData{tutor-start=55,tutor-end=56}{x}\right), x[0,π4]\htmlData{tutor-start=0,tutor-end=1}{x} \htmlData{tutor-start=2,tutor-end=6}{\in }\left[\htmlData{tutor-start=12,tutor-end=13}{0}\htmlData{tutor-start=13,tutor-end=14}{,} \frac{\htmlData{tutor-start=21,tutor-end=24}{\pi}}{\htmlData{tutor-start=26,tutor-end=27}{4}}\right], 求函数 y=g(x)\htmlData{tutor-start=0,tutor-end=1}{y}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=3}{g}\htmlData{tutor-start=3,tutor-end=4}{(}\htmlData{tutor-start=4,tutor-end=5}{x}\htmlData{tutor-start=5,tutor-end=6}{)} 值域.

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 18 题

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19

解答题 · 数学竞赛/待细分

在研究某市交通情况时,道路密度是指该路段上一定时间内通过的车辆数量除以时间,车辆密度是指该路段一定时间内通过的车辆数除以该路段的长度。现定义交通流量为 v=qx\htmlData{tutor-start=0,tutor-end=1}{v} \htmlData{tutor-start=2,tutor-end=3}{=} \frac{\htmlData{tutor-start=10,tutor-end=11}{q}}{\htmlData{tutor-start=13,tutor-end=14}{x}},其中 x\htmlData{tutor-start=0,tutor-end=1}{x} 为道路密度,q\htmlData{tutor-start=0,tutor-end=1}{q} 为车辆密度。据调查某路段的交通流量有如下规律:v={100135(13)80x,0<x<40,k(x40)+85,40x80,\htmlData{tutor-start=0,tutor-end=1}{v} \htmlData{tutor-start=2,tutor-end=3}{=} \begin{cases} \htmlData{tutor-start=18,tutor-end=19}{1}\htmlData{tutor-start=19,tutor-end=20}{0}\htmlData{tutor-start=20,tutor-end=21}{0} \htmlData{tutor-start=22,tutor-end=23}{-} \htmlData{tutor-start=24,tutor-end=25}{1}\htmlData{tutor-start=25,tutor-end=26}{3}\htmlData{tutor-start=26,tutor-end=27}{5} \left(\frac{\htmlData{tutor-start=40,tutor-end=41}{1}}{\htmlData{tutor-start=43,tutor-end=44}{3}}\right)^{\frac{\htmlData{tutor-start=60,tutor-end=61}{8}\htmlData{tutor-start=61,tutor-end=62}{0}}{\htmlData{tutor-start=64,tutor-end=65}{x}}}\htmlData{tutor-start=67,tutor-end=68}{,} & \htmlData{tutor-start=71,tutor-end=72}{0} \htmlData{tutor-start=73,tutor-end=74}{<} \htmlData{tutor-start=75,tutor-end=76}{x} \htmlData{tutor-start=77,tutor-end=78}{<} \htmlData{tutor-start=79,tutor-end=80}{4}\htmlData{tutor-start=80,tutor-end=81}{0}\htmlData{tutor-start=81,tutor-end=82}{,} \\ \htmlData{tutor-start=86,tutor-end=87}{-}\htmlData{tutor-start=87,tutor-end=88}{k}\htmlData{tutor-start=88,tutor-end=89}{(}\htmlData{tutor-start=89,tutor-end=90}{x}\htmlData{tutor-start=90,tutor-end=91}{-}\htmlData{tutor-start=91,tutor-end=92}{4}\htmlData{tutor-start=92,tutor-end=93}{0}\htmlData{tutor-start=93,tutor-end=94}{)} \htmlData{tutor-start=95,tutor-end=96}{+} \htmlData{tutor-start=97,tutor-end=98}{8}\htmlData{tutor-start=98,tutor-end=99}{5}\htmlData{tutor-start=99,tutor-end=100}{,} & \htmlData{tutor-start=103,tutor-end=104}{4}\htmlData{tutor-start=104,tutor-end=105}{0} \htmlData{tutor-start=106,tutor-end=116}{\leqslant }\htmlData{tutor-start=116,tutor-end=117}{x} \htmlData{tutor-start=118,tutor-end=128}{\leqslant }\htmlData{tutor-start=128,tutor-end=129}{8}\htmlData{tutor-start=129,tutor-end=130}{0}\htmlData{tutor-start=130,tutor-end=131}{,} \end{cases} (其中 k>0\htmlData{tutor-start=0,tutor-end=1}{k} \htmlData{tutor-start=2,tutor-end=3}{>} \htmlData{tutor-start=4,tutor-end=5}{0})。 (1) 当交通流量大于 95 时,求道路密度 x\htmlData{tutor-start=0,tutor-end=1}{x} 的取值范围; (2) 若道路密度 x=80\htmlData{tutor-start=0,tutor-end=1}{x}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=3}{8}\htmlData{tutor-start=3,tutor-end=4}{0} 时,测得交通流量 v=50\htmlData{tutor-start=0,tutor-end=1}{v}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=3}{5}\htmlData{tutor-start=3,tutor-end=4}{0},求车辆密度 q\htmlData{tutor-start=0,tutor-end=1}{q} 的最大值。

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 19 题

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该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

20

解答题 · 平面几何

b>0\htmlData{tutor-start=0,tutor-end=1}{b} \htmlData{tutor-start=2,tutor-end=3}{>} \htmlData{tutor-start=4,tutor-end=5}{0}。如图所示,在平面直角坐标系 xOy\htmlData{tutor-start=0,tutor-end=1}{x}\htmlData{tutor-start=1,tutor-end=2}{O}\htmlData{tutor-start=2,tutor-end=3}{y} 中,A(xA,yA)\htmlData{tutor-start=0,tutor-end=1}{A}\htmlData{tutor-start=1,tutor-end=2}{(}\htmlData{tutor-start=2,tutor-end=3}{x}_{\htmlData{tutor-start=5,tutor-end=6}{A}}\htmlData{tutor-start=7,tutor-end=8}{,} \htmlData{tutor-start=9,tutor-end=10}{y}_{\htmlData{tutor-start=12,tutor-end=13}{A}}\htmlData{tutor-start=14,tutor-end=15}{)} 是双曲线 C1:x24y2b2=1\htmlData{tutor-start=0,tutor-end=1}{C}_{\htmlData{tutor-start=3,tutor-end=4}{1}}\htmlData{tutor-start=5,tutor-end=6}{:} \frac{\htmlData{tutor-start=13,tutor-end=14}{x}^{\htmlData{tutor-start=16,tutor-end=17}{2}}}{\htmlData{tutor-start=20,tutor-end=21}{4}} \htmlData{tutor-start=23,tutor-end=24}{-} \frac{\htmlData{tutor-start=31,tutor-end=32}{y}^{\htmlData{tutor-start=34,tutor-end=35}{2}}}{\htmlData{tutor-start=38,tutor-end=39}{b}^{\htmlData{tutor-start=41,tutor-end=42}{2}}} \htmlData{tutor-start=45,tutor-end=46}{=} \htmlData{tutor-start=47,tutor-end=48}{1} 和圆 C2:x2+y2=4+b2\htmlData{tutor-start=0,tutor-end=1}{C}_{\htmlData{tutor-start=3,tutor-end=4}{2}}\htmlData{tutor-start=5,tutor-end=6}{:} \htmlData{tutor-start=7,tutor-end=8}{x}^{\htmlData{tutor-start=10,tutor-end=11}{2}} \htmlData{tutor-start=13,tutor-end=14}{+} \htmlData{tutor-start=15,tutor-end=16}{y}^{\htmlData{tutor-start=18,tutor-end=19}{2}} \htmlData{tutor-start=21,tutor-end=22}{=} \htmlData{tutor-start=23,tutor-end=24}{4} \htmlData{tutor-start=25,tutor-end=26}{+} \htmlData{tutor-start=27,tutor-end=28}{b}^{\htmlData{tutor-start=30,tutor-end=31}{2}} 在第一象限内的交点,曲线 Γ\htmlData{tutor-start=0,tutor-end=6}{\Gamma}C1\htmlData{tutor-start=0,tutor-end=1}{C}_{\htmlData{tutor-start=3,tutor-end=4}{1}} 中满足 xxA\htmlData{tutor-start=0,tutor-end=1}{|}\htmlData{tutor-start=1,tutor-end=2}{x}\htmlData{tutor-start=2,tutor-end=3}{|} \htmlData{tutor-start=4,tutor-end=14}{\geqslant }\htmlData{tutor-start=14,tutor-end=15}{x}_{\htmlData{tutor-start=17,tutor-end=18}{A}} 的部分和 C2\htmlData{tutor-start=0,tutor-end=1}{C}_{\htmlData{tutor-start=3,tutor-end=4}{2}} 中满足 xxA\htmlData{tutor-start=0,tutor-end=1}{|}\htmlData{tutor-start=1,tutor-end=2}{x}\htmlData{tutor-start=2,tutor-end=3}{|} \htmlData{tutor-start=4,tutor-end=14}{\geqslant }\htmlData{tutor-start=14,tutor-end=15}{x}_{\htmlData{tutor-start=17,tutor-end=18}{A}} 的部分构成。 (1) 若 xA=6\htmlData{tutor-start=0,tutor-end=1}{x}_{\htmlData{tutor-start=3,tutor-end=4}{A}} \htmlData{tutor-start=6,tutor-end=7}{=} \sqrt{\htmlData{tutor-start=14,tutor-end=15}{6}},求 b\htmlData{tutor-start=0,tutor-end=1}{b} 的值; (2) 若 b=5\htmlData{tutor-start=0,tutor-end=1}{b} \htmlData{tutor-start=2,tutor-end=3}{=} \sqrt{\htmlData{tutor-start=10,tutor-end=11}{5}}F1,F2\htmlData{tutor-start=0,tutor-end=1}{F}_{\htmlData{tutor-start=3,tutor-end=4}{1}}\htmlData{tutor-start=5,tutor-end=6}{,} \htmlData{tutor-start=7,tutor-end=8}{F}_{\htmlData{tutor-start=10,tutor-end=11}{2}} 分别为 Γ\htmlData{tutor-start=0,tutor-end=6}{\Gamma}x\htmlData{tutor-start=0,tutor-end=1}{x} 轴的左、右两个交点,第一象限内的点 P\htmlData{tutor-start=0,tutor-end=1}{P} 也在 Γ\htmlData{tutor-start=0,tutor-end=6}{\Gamma} 上,且 PF1=8\htmlData{tutor-start=0,tutor-end=1}{|}\htmlData{tutor-start=1,tutor-end=2}{P}\htmlData{tutor-start=2,tutor-end=3}{F}_{\htmlData{tutor-start=5,tutor-end=6}{1}}\htmlData{tutor-start=7,tutor-end=8}{|} \htmlData{tutor-start=9,tutor-end=10}{=} \htmlData{tutor-start=11,tutor-end=12}{8},求 F1PF2\htmlData{tutor-start=0,tutor-end=7}{\angle }\htmlData{tutor-start=7,tutor-end=8}{F}_{\htmlData{tutor-start=10,tutor-end=11}{1}} \htmlData{tutor-start=13,tutor-end=14}{P} \htmlData{tutor-start=15,tutor-end=16}{F}_{\htmlData{tutor-start=18,tutor-end=19}{2}} 的大小; (3) 过点 S(0,b22+2)\htmlData{tutor-start=0,tutor-end=1}{S}\left(\htmlData{tutor-start=7,tutor-end=8}{0}\htmlData{tutor-start=8,tutor-end=9}{,} \frac{\htmlData{tutor-start=16,tutor-end=17}{b}^{\htmlData{tutor-start=19,tutor-end=20}{2}}}{\htmlData{tutor-start=23,tutor-end=24}{2}} \htmlData{tutor-start=26,tutor-end=27}{+} \htmlData{tutor-start=28,tutor-end=29}{2}\right) 作斜率为 b2\htmlData{tutor-start=0,tutor-end=1}{-}\frac{\htmlData{tutor-start=7,tutor-end=8}{b}}{\htmlData{tutor-start=10,tutor-end=11}{2}} 的直线 l\htmlData{tutor-start=0,tutor-end=1}{l}。若 l\htmlData{tutor-start=0,tutor-end=1}{l}Γ\htmlData{tutor-start=0,tutor-end=6}{\Gamma} 恰有两个不同的公共点,记为 M,N\htmlData{tutor-start=0,tutor-end=1}{M}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{N},用 b\htmlData{tutor-start=0,tutor-end=1}{b} 表示 OMON\overrightarrow{\htmlData{tutor-start=16,tutor-end=17}{O}\htmlData{tutor-start=17,tutor-end=18}{M}} \htmlData{tutor-start=20,tutor-end=26}{\cdot }\overrightarrow{\htmlData{tutor-start=42,tutor-end=43}{O}\htmlData{tutor-start=43,tutor-end=44}{N}},并求当 b\htmlData{tutor-start=0,tutor-end=1}{b} 变化时,OMON\overrightarrow{\htmlData{tutor-start=16,tutor-end=17}{O}\htmlData{tutor-start=17,tutor-end=18}{M}} \htmlData{tutor-start=20,tutor-end=26}{\cdot }\overrightarrow{\htmlData{tutor-start=42,tutor-end=43}{O}\htmlData{tutor-start=43,tutor-end=44}{N}} 的取值范围。

原卷图示 1
原卷图示 1原卷第 2 页 · qwen3.7-plus_layout_detection · 需复核

题解状态:标准答案与规范题解待补充

题目标签:上海卷第 20 题

解题过程

该题已完成题面、原题号、PDF 来源锚定和题目级特征标注;答案、证明步骤与教材关联尚未录入。

21

解答题 · 代数

对于至少有三项的有穷实数数列 {an}\htmlData{tutor-start=0,tutor-end=2}{\{}\htmlData{tutor-start=2,tutor-end=3}{a}_{\htmlData{tutor-start=5,tutor-end=6}{n}}\htmlData{tutor-start=7,tutor-end=9}{\}},若 a2a1a3a1ama1\htmlData{tutor-start=0,tutor-end=1}{|}\htmlData{tutor-start=1,tutor-end=2}{a}_{\htmlData{tutor-start=4,tutor-end=5}{2}} \htmlData{tutor-start=7,tutor-end=8}{-} \htmlData{tutor-start=9,tutor-end=10}{a}_{\htmlData{tutor-start=12,tutor-end=13}{1}}\htmlData{tutor-start=14,tutor-end=15}{|} \htmlData{tutor-start=16,tutor-end=26}{\leqslant }\htmlData{tutor-start=26,tutor-end=27}{|}\htmlData{tutor-start=27,tutor-end=28}{a}_{\htmlData{tutor-start=30,tutor-end=31}{3}} \htmlData{tutor-start=33,tutor-end=34}{-} \htmlData{tutor-start=35,tutor-end=36}{a}_{\htmlData{tutor-start=38,tutor-end=39}{1}}\htmlData{tutor-start=40,tutor-end=41}{|} \htmlData{tutor-start=42,tutor-end=52}{\leqslant }\cdots \htmlData{tutor-start=59,tutor-end=69}{\leqslant }\htmlData{tutor-start=69,tutor-end=70}{|}\htmlData{tutor-start=70,tutor-end=71}{a}_{\htmlData{tutor-start=73,tutor-end=74}{m}} \htmlData{tutor-start=76,tutor-end=77}{-} \htmlData{tutor-start=78,tutor-end=79}{a}_{\htmlData{tutor-start=81,tutor-end=82}{1}}\htmlData{tutor-start=83,tutor-end=84}{|}(其中 m\htmlData{tutor-start=0,tutor-end=1}{m}{an}\htmlData{tutor-start=0,tutor-end=2}{\{}\htmlData{tutor-start=2,tutor-end=3}{a}_{\htmlData{tutor-start=5,tutor-end=6}{n}}\htmlData{tutor-start=7,tutor-end=9}{\}} 的项数),则称具有性质 P\htmlData{tutor-start=0,tutor-end=1}{P}。 (1) 分别判断数列 3,2,5,1\htmlData{tutor-start=0,tutor-end=1}{3}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{2}\htmlData{tutor-start=4,tutor-end=5}{,} \htmlData{tutor-start=6,tutor-end=7}{5}\htmlData{tutor-start=7,tutor-end=8}{,} \htmlData{tutor-start=9,tutor-end=10}{1} 与数列 4,3,2,5,1\htmlData{tutor-start=0,tutor-end=1}{4}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{3}\htmlData{tutor-start=4,tutor-end=5}{,} \htmlData{tutor-start=6,tutor-end=7}{2}\htmlData{tutor-start=7,tutor-end=8}{,} \htmlData{tutor-start=9,tutor-end=10}{5}\htmlData{tutor-start=10,tutor-end=11}{,} \htmlData{tutor-start=12,tutor-end=13}{1} 是否具有性质 P\htmlData{tutor-start=0,tutor-end=1}{P},并说明理由; (2) 已知首项为 1,公比为 q\htmlData{tutor-start=0,tutor-end=1}{q},项数为 10 的等比数列 {an}\htmlData{tutor-start=0,tutor-end=2}{\{}\htmlData{tutor-start=2,tutor-end=3}{a}_{\htmlData{tutor-start=5,tutor-end=6}{n}}\htmlData{tutor-start=7,tutor-end=9}{\}} 具有性质 P\htmlData{tutor-start=0,tutor-end=1}{P},求 q\htmlData{tutor-start=0,tutor-end=1}{q} 的取值范围; (3) 给定正整数 m4\htmlData{tutor-start=0,tutor-end=1}{m} \htmlData{tutor-start=2,tutor-end=12}{\geqslant }\htmlData{tutor-start=12,tutor-end=13}{4}。设数列 {an}\htmlData{tutor-start=0,tutor-end=2}{\{}\htmlData{tutor-start=2,tutor-end=3}{a}_{\htmlData{tutor-start=5,tutor-end=6}{n}}\htmlData{tutor-start=7,tutor-end=9}{\}}1,2,,m\htmlData{tutor-start=0,tutor-end=1}{1}\htmlData{tutor-start=1,tutor-end=2}{,} \htmlData{tutor-start=3,tutor-end=4}{2}\htmlData{tutor-start=4,tutor-end=5}{,} \cdots\htmlData{tutor-start=12,tutor-end=13}{,} \htmlData{tutor-start=14,tutor-end=15}{m} 的一个排列,项数为 m1\htmlData{tutor-start=0,tutor-end=1}{m}\htmlData{tutor-start=1,tutor-end=2}{-}\htmlData{tutor-start=2,tutor-end=3}{1} 的数列 {bn}\htmlData{tutor-start=0,tutor-end=2}{\{}\htmlData{tutor-start=2,tutor-end=3}{b}_{\htmlData{tutor-start=5,tutor-end=6}{n}}\htmlData{tutor-start=7,tutor-end=9}{\}} 满足 bk=ak+1\htmlData{tutor-start=0,tutor-end=1}{b}_{\htmlData{tutor-start=3,tutor-end=4}{k}} \htmlData{tutor-start=6,tutor-end=7}{=} \htmlData{tutor-start=8,tutor-end=9}{a}_{\htmlData{tutor-start=11,tutor-end=12}{k}\htmlData{tutor-start=12,tutor-end=13}{+}\htmlData{tutor-start=13,tutor-end=14}{1}} (k=1,2,,m1\htmlData{tutor-start=0,tutor-end=1}{k}\htmlData{tutor-start=1,tutor-end=2}{=}\htmlData{tutor-start=2,tutor-end=3}{1}\htmlData{tutor-start=3,tutor-end=4}{,} \htmlData{tutor-start=5,tutor-end=6}{2}\htmlData{tutor-start=6,tutor-end=7}{,} \cdots\htmlData{tutor-start=14,tutor-end=15}{,} \htmlData{tutor-start=16,tutor-end=17}{m}\htmlData{tutor-start=17,tutor-end=18}{-}\htmlData{tutor-start=18,tutor-end=19}{1}),且 {an}\htmlData{tutor-start=0,tutor-end=2}{\{}\htmlData{tutor-start=2,tutor-end=3}{a}_{\htmlData{tutor-start=5,tutor-end=6}{n}}\htmlData{tutor-start=7,tutor-end=9}{\}}{bn}\htmlData{tutor-start=0,tutor-end=2}{\{}\htmlData{tutor-start=2,tutor-end=3}{b}_{\htmlData{tutor-start=5,tutor-end=6}{n}}\htmlData{tutor-start=7,tutor-end=9}{\}} 都具有性质 P\htmlData{tutor-start=0,tutor-end=1}{P},求所有满足条件的数列 {an}\htmlData{tutor-start=0,tutor-end=2}{\{}\htmlData{tutor-start=2,tutor-end=3}{a}_{\htmlData{tutor-start=5,tutor-end=6}{n}}\htmlData{tutor-start=7,tutor-end=9}{\}}

题解状态:标准答案与规范题解待补充

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